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Julli [10]
3 years ago
13

What happens to the concentration of both H3O+ and OH- ions as water is added to a base?

Chemistry
1 answer:
DanielleElmas [232]3 years ago
6 0

Answer:

The concentration of H₃O⁺ ions increase whereas the concentration of the OH⁻ decreases.

Explanation:

The water, H₂O, has its own equilibrium thus:

2H₂O(l) ⇄ OH⁻(aq) + H₃O⁺(aq)

Where the water equilibrium constant, Kw, is defined as:

Kw = 1x10⁻¹⁴ = [OH⁻] [H₃O⁺]

The addition of a base represents the increasing of [OH⁻]. that means the concentration of OH⁻ ions.

Based on LeCh principle, in an equilibrium, the addition of a product produce the decreasing in concentration of the other products trying to counteract the effect, that means the concentration of H₃O⁺ ions decreases.

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All synthetic materials ultimately come from
Leno4ka [110]

Answer:

petroleum, a fossil fuel, is extracted from the earth and mechanically transformed into fibers for clothing.

Explanation:

synthetic materials, like polyester, nylon and acrylic, don't exist naturally but are made in factories. Synthetics are created through an industrial manufacturing process in which

7 0
3 years ago
2. Have someone hold the mirror for you, slowly move at least 3 m away from the it.
Ahat [919]

Answer: Slowly move at least 3 m away from the side mirror. Observe your image as you ... Compare the images formed in different mirrors. ... but if i stand 3m away, even though there is no light, it reflects the other material it can ... is transparent so you cannot see yourself much in the mirror, that is my observation.

Explanation:

3 0
3 years ago
A solution containing a mixture of metal cations was treated with dilute HCl and no precipitate formed. Next, H2S was bubbled th
erica [24]

Answer:

Explanation:

  Ions which will  be definitely  absent -

Ag⁺ , Hg₂⁺ , Pb⁺², because their chlorides are insoluble in water.

Ba⁺² ,Ca⁺² because their carbonates are insoluble in water,

Ions which will be definitely present  

Cu⁺² , Pb⁺² . Hg⁺² , Sb⁺³ , Sn⁺² , because their sulphides are insoluble at pH = 8.

For the rest nothing can be said.

 

5 0
3 years ago
Why can a liquid change to take the shape of its container but NOT expand to fill the container itself?
tiny-mole [99]

Answer: Option (C) is the correct answer.

Explanation:

Molecules in a liquid have less force of attraction as compared to solids. But liquid molecules have more force of attraction as compared to gases.

Since molecules of a gas are held together by weak Vander waal forces, therefore, they expand to fill the container whereas molecules in a liquid are not expanded in a container like gases because of more force of attraction within molecules of liquids as compared to gases.

Hence, a liquid can take the shape of container in which it is kept.

Thus, we can conclude that out of the given options, a liquid change to take the shape of its container but NOT expand to fill the container itself because the particles of a liquid are held together loosely enough to flow, but not so loose that they expand.


4 0
3 years ago
Read 2 more answers
Consider the reaction: CH4 + 2O2 = CO2 + 2H2O
crimeas [40]

Answer:

The answer to your question is:

a)  80 g of O2

b) O2, 15.13 g of CO2

c) It's not posible to know which is the limiting reactant.

Explanation:

Reaction                             CH4   +   2O2   ⇒   CO2   +   2H2O

a. Calculate the grams of O2 needed to react with 20.00 grams of CH4. _____________

MW CH4 = 16 g

MW O2 = 32 g

                               16 g of CH4 ----------------  2(32) g of O2

                               20 g              --------------    x

                               x = (20 x 64) / 16 = 80 g of O2

b. Given 15.00 g. of CH4 and 22.00 g. of O2, identify the limiting reactant and calculate the grams of CO2 that can be produced. LR _________ grams CO2 _________ .  

                                CH4   +   2O2   ⇒   CO2   +   2H2O

                                15 g         22 g

                                16 g of CH4 ----------------  64 g of O2

                                15 g of CH4  ---------------   x

                               x = (15 x 64) / 16 = 60 g of O2

The Limiting reactant is O2 because it is necessary 60g of O2 for 16 g of CH4 and there are only 22.

                                 CH4   +   2O2   ⇒   CO2   +   2H2O

                        64 g of O2 ------------------  44 g of CO2

                        22 g of O2 ------------------   x

                        x = (22 x 44)/ 64 = 15. 13 g of CO2

c. For the reaction CH4 + 2O2 = CO2 + 2H2O, if you have 10.31 g. of CH4 and an unknown amount of oxygen, and form 20.00 g. of CO2, i. Identify if there is a limiting reactant ______________ ii. Calculate the number of grams of the limiting reactant present if there is one. ______________  

                           CH4   +   2O2   ⇒   CO2   +   2H2O                              

                           10.31 g                     20 g

We can identify the limiting reactant if we know the quantity of the reactants, if we only know the quantity of one it is not posible to which is the limiting reactant.

4 0
2 years ago
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