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3 years ago

What happens to the concentration of both H3O+ and OH- ions as water is added to a base?

Chemistry

1 answer:

DanielleElmas [232]3 years ago

6 0

Answer:

The concentration of H₃O⁺ ions increase whereas the concentration of the OH⁻ decreases.

Explanation:

The water, H₂O, has its own equilibrium thus:

2H₂O(l) ⇄ OH⁻(aq) + H₃O⁺(aq)

Where the water equilibrium constant, Kw, is defined as:

Kw = 1x10⁻¹⁴ = [OH⁻] [H₃O⁺]

The addition of a base represents the increasing of [OH⁻]. that means the concentration of OH⁻ ions.

Based on LeCh principle, in an equilibrium, the addition of a product produce the decreasing in concentration of the other products trying to counteract the effect, that means the concentration of H₃O⁺ ions decreases.

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A binding protein binds to a ligand l with a kd of 400 nm. what is the concentration of ligand when y is (a) 0.25, (b) 0.6, (c)

lilavasa [31]

Hey there!:

The fractional saturation y is defined as :

y = [ L ] / Kd + [ L ]

where :

[ L ] = concentration of binding ligand

Kd = 400 nm

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4 years ago

Carbohydrate atoms usually have how hydrogen atoms as compared to oxygen atoms?

Inessa05 [86]

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3 years ago

Which net ionic equation would match this description of a chemical reaction: When a

krok68 [10]

Answer:

$3Mg^{2+}(aq.)+2PO_{4}^{3-}(aq.)\rightarrow Mg_{3}(PO_{4})_{2}(s)$

Explanation:

$Mg(NO_{3})_{2}$ , $Na_{3}PO_{4}$ are strong electrolytes. Hence they are fully ionized in aqueous solution.

$Mg_{3}(PO_{4})_{2}$ is a sparingly soluble salt. Hence it remains undissociated in aqueous solution.

So, total ionic equation:

$3Mg^{2+}(aq.)+6NO_{3}^{-}(aq.)+6Na^{+}(aq.)+2PO_{4}^{3-}(aq.)\rightarrow Mg_{3}(PO_{4})_{2}(s)+6Na^{+}(aq.)+6NO_{3}^{-}(aq.)$

Net ionic equation is written by omitting spectator ions from total ionic equation.

Here, $Na^{+}$ and $NO_{3}^{-}$ ions are spectator ions as they remain present on both side of total ionic equation.

So, net ionic equation:

$3Mg^{2+}(aq.)+2PO_{4}^{3-}(aq.)\rightarrow Mg_{3}(PO_{4})_{2}(s)$

So, option (d) is correct.

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3 years ago

Three compounds containing potassium and oxygen are compared. Analysis shows that for each 1.00 g of O, the compounds have 1.22

kicyunya [14]

The law of proportion states that elements combine in whole number ratios. The gram readings for K are multiples of each other, both in grams and moles.
Let us compare the ratios:
2.44 grams/1.22 grams = 2
4.89 grams/2.44 grams = 2

Therefore, Potassium always combines with Oxygen in a ratio of 2 is to 1.

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4 years ago

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Vesnalui [34]

Answer:

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3 years ago