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2 years ago

PLEASE ANSWER WILL GIVE BRAINLIEST IF CORRECT!!!

Mathematics

2 answers:

swat322 years ago

8 0

vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv

Airida [17]2 years ago

5 0

Answer:

x = 118 units

Step-by-step explanation:

tan 50° = x/99

x = 99(tan 50°)

x = 117.9

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Find the GCF of the following monomials.<br> -50m⁴ n⁷ and 40m² n¹⁰

babunello [35]

Greetings!

We can factor this expression/ the GCF is:
$-10m^2n^7$

$(-10m^2n^7)(5m^2-4n^3)$

Hope this helps.
-Benjamin

8 0

3 years ago

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Solve -2/3 n< 16 What is the following must be true about the causes and the results Grove select the

pantera1 [17]

Answer:

-24

Step-by-step explanation:

you divide -2/3 by each side and that will give you your answer

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3 years ago

Find the differential coefficient of <br><img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^

Gemiola [76]

Answer:

$\rm \displaystyle y' = 2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x}$

Step-by-step explanation:

we would like to figure out the differential coefficient of $e^{2x}(1+\ln(x))$

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

$\displaystyle y = {e}^{2x} \cdot (1 + \ln(x) )$

to do so distribute:

$\displaystyle y = {e}^{2x} + \ln(x) \cdot {e}^{2x}$

take derivative in both sides which yields:

$\displaystyle y' = \frac{d}{dx} ( {e}^{2x} + \ln(x) \cdot {e}^{2x} )$

by sum derivation rule we acquire:

$\rm \displaystyle y' = \frac{d}{dx} {e}^{2x} + \frac{d}{dx} \ln(x) \cdot {e}^{2x}$

Part-A: differentiating $e^{2x}$

$\displaystyle \frac{d}{dx} {e}^{2x}$

the rule of composite function derivation is given by:

$\rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dg} f(g(x)) \times \frac{d}{dx} g(x)$

so let g(x) [2x] be u and transform it:

$\displaystyle \frac{d}{du} {e}^{u} \cdot \frac{d}{dx} 2x$

differentiate:

$\displaystyle {e}^{u} \cdot 2$

substitute back:

$\displaystyle \boxed{2{e}^{2x} }$

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

$\displaystyle \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)$

let

$f(x) \implies \ln(x)$
$g(x) \implies {e}^{2x}$

substitute

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \frac{d}{dx}( \ln(x) ) {e}^{2x} + \ln(x) \frac{d}{dx} {e}^{2x}$

differentiate:

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \boxed{\frac{1}{x} {e}^{2x} + 2\ln(x) {e}^{2x} }$

Final part:

substitute what we got:

$\rm \displaystyle y' = \boxed{2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x} }$

and we're done!

6 0

3 years ago

Find x and y, given that line WS and line VT are parallel. Show all work!

bulgar [2K]

In the given diagram, the traingles USW and UTV are similar triangles and thus the following ratio equality applies to them.

$\frac{VT}{WS} =\frac{VU}{WU}=\frac{TU}{SU}$ ..........(Equation 1)

Checking the diagram given, we see that:

VT=y, WS=22, VU=8, ST=x-2

WU=WV+VU=12+8=20

TU=5

SU=ST+TU=(x-2)+5=x+3

Thus, substituting the required values in (Equation 1) we get:

$\frac{y}{22}=\frac{8}{20}=\frac{5}{x+3}$

Now, as can be clearly seen, to find y we will use the first two ratios as:

$\frac{y}{22}=\frac{8}{20}$

$y=\frac{8\times 22}{20}=8.8$

In a similar manner, to find the value of x we can use the last two ratios:

$\frac{8}{20}=\frac{5}{x+3}$

After cross multiplication we get:

$5\times 20=8(x+3)$

Which can be simplified as:

$x+3=\frac{100}{8} =12.5$

Thus, $x=12.5-3=9.5$

Therefore, the required answer is:

x=9.5 and y=8.8

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3 years ago

In the wrong hands, which of the following pieces of personal information would present the greatest risk for identity theft?

Aneli [31]

Answer:

D. social security number

Step-by-step explanation:

If a thief uses your your Social Security number for financial gain, you’re a victim of financial identity theft, criminal identity theft and also utility fraud.

Hope this will helpful.

Thank you.

6 0

3 years ago

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