In Florida, more than 20,000 crashes are alcohol related
Answer:
Explanation:
These are present in group two and have two valance electrons.
All have high melting and boiling point.
All alkaline earth metals form salt with halogens.e.g
Mg + Cl₂ → MgCl₂
Ba + Br₂ → BaBr₂
Mg + Br₂ → MgBr₂
Ca + Br₂ → CaBr₂
They react with oxygen and form oxides of respective metal.
2Mg + O₂ → 2MgO
2Ba + O₂ → 2BaO
2Ca + O₂ → 2CaO
these oxides form hydroxide when react with water,
MgO + H₂O → Mg(OH)₂
BaO + H₂O → Ba(OH)₂
CaO + H₂O → Ca(OH)₂
With nitrogen it produced nitride,
3Mg + N₂ → Mg₃N₂
3Ba + N₂ → Ba₃N₂
3Ca + N₂ → Ca₃N₂
With acid like HCl,
Mg + 2HCl → MgCl₂ + H₂
Ba + 2HCl → BaCl₂ + H₂
Ca + 2HCl → CaCl₂ + H₂
Answer:
Option d)3.32 g is correct.
Explanation:
hope this helps
Answer:
CHOOH (aq) + H₂O (l) ⇄ HCOO⁻ (aq) + H₃O⁺ (aq)
Weak acid Base Conj. strong base Conj. acid
H₂S (aq) + NH₃ (aq) ⇄ NH₄⁺(aq) + HS⁻ (aq)
Weak acid Weak Base Conj. strong acid Conj. strong base
Explanation:
To determine the acid-base pairs in the example below we follow the Brownsted Lowry theory.
An acid releases protons
A base accepts protons
CHOOH (aq) + H₂O (l) ↔ HCOO⁻ (aq) + H₃O⁺ (aq)
Formic reacts to water in order to produce formate and hydroniums
Formic release a proton → Acid
Formate can accepted the proton → Conjugate base
Water will be the base, because it will acepted the proton, so the hydronium will be the conjugate acid, because it will release the proton to become water again.
H₂S (aq) + NH₃ (aq) ⇄ NH₄⁺(aq) + HS⁻ (aq)
The sulfidric behaves as an acid, it release the proton to ammonia.
The acid sulfide, becomes the base. It can accept the proton for being, H₂S again.
Then the ammonia is the base (it can accept H⁺) and the ammonium is the conjugate acid (it release the H⁺)
Answer: True
Explanation: Intensive property does not depend on the amount of matter. Specific internal energy is an intensive property.