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charle [14.2K]
3 years ago
5

What is the sum of –18 and 12? A. –6 B. –12 C. 12 D. 6

Mathematics
2 answers:
docker41 [41]3 years ago
7 0

your answer is A.-6, i think its helpful

PolarNik [594]3 years ago
6 0

Answer:

A: -6

Step-by-step explanation:

Flip around the question

what is 12 - 18

If you count the numbers in between 12 and 18

You get 6

So now just make the answer negative

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Consumer Math work. Please help
Firdavs [7]

Answer:

$337.5

Step-by-step explanation:

He would get $337.5 because if he gets $11.25 every hour you just multiply $11.25 by 30 hours.

7 0
3 years ago
Can someone plz help me with Algebra 2....... :) Will give Brainliest!!
Anarel [89]
Using logarithms property of log(x)+log(y)=log(xy)
so here, you can sum the equation to;
log((x+6)*(x-6))=2
so you can simply say that;
log_{8}((x+6)( x-6))=2
and by multiplying (x+6)*(x-6)
log_{8}(x^2-36)=2
and as you know also that;
a^{b}=c is same as log _{a}c=b
so you can simply state it as;
8^2=x^2-36
64=x^2-36
64+36=x^2
x^2=100
x=10
And you can check your work by substituting with 10 instead of x in the original function.
Hope this helps!
6 0
3 years ago
Which of the following rational numbers is equal to 2 point 4 with bar over 4? twenty two over nine twenty four over nine twenty
qaws [65]

Answer:

Twenty two over nine.

Step-by-step explanation:

The bar over the 4 means that 4 is recurring .44444.........  It goes on with out bounds and is equal to 4/9.

So 2.4 = 2 4/9

= 22/9.

7 0
3 years ago
Read 2 more answers
Why does the graph of a proportional relationship must pass through the origin (0,0)
ELEN [110]

Answer:

Directly proportional relationships always pass through the origin (0,0). There are other linear relationships that do not pass through the origin.

4 0
4 years ago
Suppose a spherical balloon grows in such a way that after t seconds, its volume is V = 4 sqrt(t) cm3.
chubhunter [2.5K]
The volume at time <span>t = 25 seconds
since </span><span> V = 4 sqrt(t) cm3, 
 V(5)= 4*</span><span>sqrt(25)cm^3=4*5=20cm^3</span>
3 0
4 years ago
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