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kati45 [8]
2 years ago
14

Identify the property demonstrated

Mathematics
1 answer:
ale4655 [162]2 years ago
8 0

Answer:

  • D. Product of Powers Property

Step-by-step explanation:

  • 4^3 * 4^7 = 4^{3 + 7}

<u>The Product of Powers Property states: </u>

  • <em>when multiplying two exponents with the same base, you can add the exponents and keep the base</em>
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Pepe tenía dinero ahorrado en su alcancia pero le retiró $75 para comprar un jugete. Ahora tiene $250 en su alcancia ¿Cuánto din
gregori [183]
El tenia $325

$250+$75=$325

Espero q te ayude :)
4 0
3 years ago
Lauren bikes 4/3 miles in 1/10 hour.how long does it take her to bike one mile
lisabon 2012 [21]

Answer:

3/40 hours

Step-by-step explanation:

4 0
3 years ago
An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of
ANEK [815]

Answer:

(a) 0.152

(b) 0.789

(c) 0.906

Step-by-step explanation:

Let's denote the events as follows:

<em>F</em> = The word free occurs in an email

<em>S</em> = The email is spam

<em>V</em> = The email is valid.

The information provided to us are:

  • The probability of the word free occurring in a spam message is,             P(F|S)=0.60
  • The probability of the word free occurring in a valid message is,             P(F|V)=0.04
  • The probability of spam messages is,

        P(S)=0.20

First let's compute the probability of valid messages:

P (V) = 1 - P(S)\\=1-0.20\\=0.80

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The probability that a message contains the word free is:

P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is spam provided that it contains free is:

P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is valid provided that it does not contain free is:

P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566

The probability that a message is valid provided that it does not contain free is approximately 0.906.

4 0
4 years ago
5.
neonofarm [45]

Answer:

3 kids and 5 adults

Step-by-step explanation:

3×5.5 = 16.5

5×7.25= 36.25

16.5+36.25= 52.75

4 0
3 years ago
What is the opposite of the opposite of -3/8
Svetllana [295]

answer: c. -3/8

Explanation: do it step by step so opposite of -3/8 is 3/8 the opposite of 3 /8 is -3/8

it sounds complicated but it is actually easy

4 0
4 years ago
Read 2 more answers
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