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marta [7]
2 years ago
6

Write the equation of a line that is parallel with a y = -2/3 x + 2 and goes

Mathematics
1 answer:
zhannawk [14.2K]2 years ago
5 0

Answer:

y = -2/3x - 2

Step-by-step explanation:

Parallel lines have the same slope so slope = -2/3

Given (-3,0)

Slope-intercept: y = mx + b

0 = -2/3(-3) + b

0 = 2 + b

b = -2

then y = -2/3x - 2

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Need help on this question please!
podryga [215]

Answer:

The answer is -46

6 0
3 years ago
Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips. Urn II contains three red
Neporo4naja [7]

Answer:

Multiple answers

Step-by-step explanation:

The original urns have:

  1. Urn 1 = 2 red + 4 white = 6 chips
  2. Urn 2 = 3 red + 1 white = 4 chips

We take one chip from the first urn, so we have:

The probability of take a red one is : \frac{1}{3} (2 red from 6 chips(2/6=1/2))

For a white one is: \frac{2}{3}(4 white from 6 chips(4/6=(2/3))

Then we put this chip into the second urn:

We have two possible cases:

  • First if the chip we got from the first urn was white. The urn 2 now has 3 red + 2 whites = 5 chips
  • Second if the chip we got from the first urn was red. The urn two now has 4 red + 1 white = 5 chips

If we select a chip from the urn two:

  • In the first case the probability of taking a white one is of:  \frac{2}{5} = 40%  ( 2 whites of 5 chips)
  • In the second case the probability of taking a white one is of:  \frac{1}{5} = 20%  ( 1 whites of 5 chips)

This problem is a dependent event because the final result depends of the first chip we got from the urn 1.

For the fist case we multiply :

\frac{4}{6} x \frac{2}{5} = \frac{4}{15} = 26.66%   ( \frac{4}{6} the probability of taking a white chip from the urn 1, \frac{2}{5}  the probability of taking a white chip from urn two)

For the second case we multiply:

\frac{1}{3} x \frac{1}{5} = \frac{1}{30} = .06%   ( \frac{1}{3} the probability of taking a red chip from the urn 1, \frac{1}{5}   the probability of taking a white chip from the urn two)

8 0
4 years ago
Express the sum of the polymonial 3x^2+15x-56 and the square of the binomial (x-8) as a polynomial in standard form.
tester [92]

Given:

Polynomial is 3x^2+15x-56.

To find:

The sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form.

Solution:

The sum of given polynomial and the square of the binomial (x-8) is

3x^2+15x-56+(x-8)^2

=3x^2+15x-56+x^2-2(x)(8)+8^2    [\because (a-b)^2=a^2-2ab+b^2]

=3x^2+15x-56+x^2-16x+64

On combining like terms, we get

=(3x^2+x^2)+(15x-16x)+(-56+64)

=4x^2-x+8

Therefore, the sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form is 4x^2-x+8.

7 0
3 years ago
Solve the inequality<br> 7x&lt;5x-8
Aleksandr [31]
Minust 5x both sides
7x-5x<5x-5x-8
2x<-8
divide by 2 both sides
x<-4
6 0
3 years ago
10(5 - n) - 1 = 29<br><br> n = ?<br> Help!
nydimaria [60]

n = 2

distribute and simplify left side of equation

50 - 10n - 1 = 29

49 - 10n = 29 ( subtract 49 from both sides )

- 10n = 29 - 49 = - 20

n = \frac{-20}{-10} = 2



5 0
4 years ago
Read 2 more answers
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