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Anni [7]
2 years ago
6

A gas occupies a volume of 50 mL and 630 mmHg. At what temperature in Celsius, would the pressure be 101.3 kPa if the volume rem

ains constant? ​
Chemistry
1 answer:
KATRIN_1 [288]2 years ago
4 0

Answer:

then it would still be 101.3

Explanation: because if it's constant that means it remained still

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How many moles of Ammonium Sulfate can be made from 30.0mol of NH3? 2NH3 + H2SO4 --> (NH4)2SO4
BartSMP [9]

Answer: 15.0 moles of (NH_4)_2SO_4 are formed from  30.0 mol of NH_3

Explanation:

The balanced chemical reaction is :

2NH_3+H_2SO_4\rightarrow (NH_4)_2SO_4

According to stoichiometry :

2 moles of NH_3 give = 1 mole of (NH_4)_2SO_4

Thus 30.0 moles of NH_3 will give =\frac{1}{2}\times 30.0=15.0moles  of (NH_4)_2SO_4

Thus 15.0 moles of (NH_4)_2SO_4 are formed from  30.0 mol of NH_3

7 0
4 years ago
What is the correct name for this formula: AI2O3?
agasfer [191]

Answer- A

Explanation- Because you have to look at the symbols and remember which symbol goes with each chemical, if you don't then you could get confused.

5 0
3 years ago
1) When 2.38g of magnesium is added to 25.0cm of 2.27 M hydrochloric acid, hydrogen gas is released.
Andrej [43]

Answer:

a. HCl.

b. 0.057 g.

c. 1.69 g.

d. 77 %.

Explanation:

Hello!

In this case, since the reaction between magnesium and hydrochloric acid is:

Mg+2HCl\rightarrow MgCl_2+H_2

Whereas there is 1:2 mole ratio between them.

a) Here, we can identify the limiting reactant as that yielded the fewest moles of hydrogen gas product via the 1:1 and 2:1 mole ratios:

n_{H_2}^{by\  HCl}=0.025L*2.27\frac{molHCl}{1L}*\frac{1molH_2}{2molHCl}  =0.0284molH_2\\\\n_{H_2}^{by\  Mg}=2.38gMg*\frac{1molMg}{24.3gMg}*\frac{1molH_2}{1molMg}=0.0979molH_2

Thus, since hydrochloric yields fewer moles of hydrogen than magnesium, we realize it is the limiting reactant.

b) Here, we use the molar mass of gaseous hydrogen (2.02 g/mol) to compute the mass:

m_{H_2}=0.0284molH_2*\frac{2.02gH_2}{1molH_2}=0.057gH_2

c) Here, we compute the mass of magnesium associated with the yielded 0.0248 moles of hydrogen:

m_{Mg}^{reacted}=0.0284molH_2*\frac{1molMg}{1molH_2}*\frac{24.3gMg}{1molMg}  =0.690gMg

Thus, the mass of excess magnesium turns out:

m_{Mg}^{excess}=2.38g-0.690g=1.69gMg

d) Finally, we compute the percent yield, considering 0.044 g is the actual yield and 0.057 g the theoretical yield:

Y=\frac{0.044g}{0.057g} *100\%\\\\Y=77\%

Best regards!

8 0
3 years ago
The density of copper is 8.92 g/mL. The mass of a piece of copper that has a volume of 10.3 mL is
m_a_m_a [10]

Answer:

The answer is

<h2>91.9 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of copper = 10.3 mL

density = 8.92 g/mL

The mass is

mass = 8.92 × 10.3 = 91.876

We have the final answer as

<h3>91.9 g</h3>

Hope this helps you

8 0
4 years ago
Electrons.<br> The carbon atom has a total of
Lunna [17]

Answer:

Six electrons.

Explanation:

A carbon atom has six protons, so it must have six electrons.

6 0
3 years ago
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