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pychu [463]
3 years ago
10

What is the rate constant of a reaction if rate = 0.2 (mol/L)/s, [A] and [B] are each 3 M, m = 1, and n = 2?

Chemistry
2 answers:
Assoli18 [71]3 years ago
7 0

Answer : The rate constant of a reaction is, 7.407\times 10^{-3}M^{-2}s^{-1}

Solution :

The general rate law expression is,

rate=k[A]^m[B]^n

where,

k = rate constant

[A] and [B] are the concentrations

m is the order of reactant A and n is the order of reactant B

Now put all the given values in the above rate law expression, we get the value for rate constant.

0.2Ms^{-1}=k\times (3M)^1\times (3M)^2

k=7.407\times 10^{-3}M^{-2}s^{-1}

Therefore, the rate constant of a reaction is, 7.407\times 10^{-3}M^{-2}s^{-1}

tino4ka555 [31]3 years ago
4 0
M= 1 and n = 2
( m+ n =  1 +2  = 3)

rate = K [A] [B]^2

0.2  = K *  3  * 3 ^2
0.2 =  K  *  3 * 9 
 K =    0.2   / 27 
K =   7.408 *  10 ^ -3  m^-2  s^-1

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Pluto is no longer considered to be a planet. Therefore, how many planets are in the solar system?
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5 0
3 years ago
Read 2 more answers
If 30 ml of water containing 15 mg of salicylate is extracted with 30 ml of chloroform, 2.59 mg of salicylate remains in the wat
In-s [12.5K]

Answer:

Distribution coefficient: 4.79

Explanation:

Distribution coefficient is the ratio between equilibrium concentration of non-aqueous phase and aqueous phase where both solvents are inmiscible. The equation for the problem is:

Distribution coefficient: Concentration in chloroform / Concentration in Water

<em>Concentration in water: 2.59mg / 30mL = 0.08633mg/mL</em>

<em>Concentration in chloroform: (15mg-2.59mg) / 30mL = 0.4137mg/mL</em>

<em />

Distribution coefficient: 0.4137mg/mL / 0.08633mg/mL

<h3>Distribution coefficient: 4.79</h3>
8 0
2 years ago
The two naturally occuring isotopes of antimony are 121Sb (57.21%) and 123Sb (42.79%), with isotopic masses of 120.904 and 122.9
emmasim [6.3K]

Answer:

The average atomic weight = 121.7598 amu

Explanation:

The average atomic weight of natural occurring antimony can be calculated as follows :

To calculate the average atomic mass the percentage abundance must be converted to decimal.

121 Sb has a percentage abundance of 57.21%, the decimal format will be

57.21/100 = 0.5721 . The value is the fractional abundance of 121 Sb .

123 Sb has a percentage abundance of 42.79%, the decimal format will be

42.79/100 = 0.4279. The value is the fractional abundance of 123 Sb .

Next step is multiplying the fractional abundance to it masses

121 Sb = 0.5721 × 120.904 = 69.169178400

123 Sb = 0.4279 × 122.904 = 52.590621600

The final step is adding the value to get the average atomic weight.

69.169178400 + 52.590621600 = 121.7598 amu

5 0
2 years ago
A reddish layer of rust can form on old iron nails and bikes. In this chemical reaction, iron reacts slowly with oxygen in the a
Molodets [167]

Answer:

Iron slowly reacts with oxygen and forms rust. In this case, the reactants are iron and oxygen. The product is rust, or iron oxide. The chemical equation looks like this:

Explanation:

iron + oxygen → iron oxide

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3 years ago
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