The initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C
<h3>How to calculate temperature?</h3>
The initial temperature of the copper metal can be calculated using the following formula on calorimetry:
Q = mc∆T
mc∆T (water) = - mc∆T (metal)
Where;
- m = mass
- c = specific heat capacity
- ∆T = change in temperature
According to this question, a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, the initial temperature of the copper is as follows:
400 × 4.18 × (42°C - 24°C) = 240 × 0.39 × (T - 24°C)
30,096 = 93.6T - 2246.4
93.6T = 32342.4
T = 345.5°C
Therefore, the initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C.
Learn more about temperature at: brainly.com/question/15267055
Answer:
The answer is "11.07 g".
Explanation:
Isoamyl alcohol is a reagent restriction
Isoamyl alcohol Moles:
![= \frac{7.5}{88.15} \\\\ =0.085](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B7.5%7D%7B88.15%7D%20%5C%5C%5C%5C%20%3D0.085)
Moles only with the shape of isoamyl acetate are equivalent to numbers.
Isoamyl acetate grams:
![= 0.085 \times 130.19\\\\ = 11.07 \ g](https://tex.z-dn.net/?f=%3D%200.085%20%5Ctimes%20130.19%5C%5C%5C%5C%20%3D%2011.07%20%5C%20g)
The formula for Silver (I) chloride is: AgCl