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3 years ago

What important points do you need to remember about combustion?

Chemistry

1 answer:

goldenfox [79]3 years ago

7 0

Explanation:

A substance burning in the presence of oxygen and leads to the formation of heat and light is called combustion.

Some important points about combustion are as follows:

Fuel should be present for burning.
Air should be present for the supply of oxygen.
There should be heat (or ignition temperature) to initiate the chemical reaction.

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Consider the equations below. (1) Fe2O3(s) → 2Fe(s) + 3 2 O2(g) (2) Fe2O3(s) + 3CO(g) → 2Fe(s)+3CO2(g) Which equation must be ad

slega [8]

Answer:

C. 3CO(g)+ $\frac{3}{2}$ O2(g)→3CO2(g)

Explanation:

7 0

3 years ago

What does a chemical formula like Na2CO3 tells us?

USPshnik [31]

It has: 2 atoms of sodium (Na) 1 atom of Carbon 3 atoms of Oxygen bound together with ionic and polar-covalent bonds

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4 years ago

Heat required to raise 1 g of a substance 1°C

Oksana_A [137]

Answer:

Specific heat

Explanation:

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3 years ago

Consider the following equilibrium:

Ainat [17]

<u>Answer: </u>The equation which is wrong is $K_p=K_c(RT)^{-5}$

<u>Explanation:</u>

For the given reaction:

$4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)$

The expression for $K_c\text{ and }K_p$ is given by:

$K_c=\frac{1}{[O_2]^3}$

$K_p=\frac{1}{[O_2]^3}$

The concentration of solids are taken to be 1, only concentration of gases and liquid states are taken. The pressure of only gases are taken.

Relationship between $K_p\text{ and }K_c$ is given by the expression:

$K_p=K_c\times (RT)^{\Delta n_g}$

where,

$\Delta n_g$ = number of moles of gaseous products - number of moles of gaseous reactants

R = gas constant

T= temperature

For the above reaction,

$\Delta n_g$ = number of moles of gaseous products - number of moles of gaseous reactants = 0 - 3 = -3

Hence, the expression for $K_p$ is:

$K_p=K_c\times (RT)^{-3}$

Therefore, the equation which is wrong is $K_p=K_c(RT)^{-5}$

7 0

4 years ago

Diatomic oxygen has a molar mass 16 times that of diatomic hydrogen. The root-mean-square speed vrms for diatomic oxygen at 50∘C

trapecia [35]

Answer:(16)(2000)m/s=32000m/s

Explanation: A diatomic oxygen has a molar mass of 16

8 0

3 years ago