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Zielflug [23.3K]
4 years ago
9

Find the antiderivative of the function: (x^4+2x^2)/x^3

Mathematics
2 answers:
Pie4 years ago
4 0

Answer: Either it is 3x to the 12 power or x+2x to the 2 power

Step-by-step explanation:

dividing exponents is the equivalent to subtracting

this leaves us with x+2x to the 2 power. then you just add. I might be wrong about breaking it down that far.

dangina [55]4 years ago
3 0
Set the function up in integral form and evaluate to find the integral.
F(x)=F(x)=12x2−ln(|x|)−1x2+C
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Suppose a certain airline uses passenger seats that are 16.2 inches wide. Assume that adult men have hip breadths that are norma
Pachacha [2.7K]

Answer:

Each adult male has a 5.05% probability of having a hip width greater than 16.2 inches.

There is a 0.01% probability that the 110 adult men will have an average hip width greater than 16.2 inches.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem

Assume that adult men have hip breadths that are normally distributed with a mean of 14.4 inches and a standard deviation of 1.1 inches. This means that \mu = 14.4, \sigma = 1.1.

What is the probability that any one of those adult male will have a hip width greater than 16.2 inches?

For each one of these adult males, the probability that they have a hip width greater than 16.2 inches is 1 subtracted by the pvalue of Z when X = 16.2. So:

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.2 - 14.4}{1.1}

Z = 1.64

Z = 1.64 has a pvalue of 0.9495.

This means that each male has a 1-0.9495 = 0.0505 = 5.05% probability of having a hip width greater than 16.2 inches.

For the average of the sample

What is the probability that the 110 adult men will have an average hip width greater than 16.2 inches?

Now, we need to find the standard deviation of the sample before using the zscore formula. That is:

s = \frac{\sigma}{\sqrt{110}} = 0.1.

Now

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.2 - 14.4}{0.1}

Z = 18

Z = 18 has a pvalue of 0.9999.

This means that there is a 1-0.9999 = 0.0001 = 0.01% probability that the 110 adult men will have an average hip width greater than 16.2 inches.

7 0
3 years ago
......................................
natima [27]

Answer:

Step-by-step explanation:

br.uh ur screen tho

6 0
3 years ago
En la figura los segmentos ED y AC son paralelos selecciona los triangulos q son 1)Triangulo ABE 2)Triangulo BCD 3) Triangulo BD
Flauer [41]

Respuesta:

Los 3 triángulos son semejantes.

Explicación paso a paso:

En estos casos nos dan a conocer los ángulos de los triángulos, por lo tanto el criterios de semejanza se reduce si más de dos de sus ángulos internos son iguales.  

Por lo tanto, sabemos que en los triángulos ABE y BCD presentan los mismos ángulos, 80°, 40° y 60° por lo que podemos afirmar que ambos triángulos son semejantes.

Ahora bien, para el triangulo BDE, podemos conocer solo un angulo del que es de 80°, pero el resto sería desconocido, lo que quiere decir que no podríamos determinar si es semejante con los otros, pero por medio de los ángulos externos determinamos que si corresponde también a 60° y 40°, por lo tanto, los 3 triángulos son semejantes.

3 0
4 years ago
a washer and a dryer cost 1020$ combined, the washer costs 70$ more than the dryer. What is the cost of the dryer?
finlep [7]

Answer:

$950

Step-by-step explanation:

x+70=1020 so subtract 70 from both sides

x=950 cost of dryer

1020-950=70 washer is 70 more than dryer

6 0
3 years ago
If ∠MHT measures 143°, what is the measure of ∠THN?
IgorC [24]
Hello,

I suppose N in on the same line as MH
Angles are thus supplementaries
180-143=37°
Answer B
6 0
3 years ago
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