Answer: a) the radius is 17.846.
b) r = 17.846+-0.044cm
c) f(×) = πr^2, a=17.846cm, L=1000cm^2
Explanation: a) circle area = A = πr^2, then r = √(A/π) = √(1000/3.14) = 17.846
c) funtion is the area equation,
Draw something similar to which has more mass in density. For example, a bowling ball and a volley ball. Both substances are similar in size but the bowling ball feels heavier than the volleyball. Label volleyball for less density and bowling ball with more density.
Answer:
45 J
Explanation:
Assuming the level at which the ball is thrown upwards is the ground level,
We can use the equations of motion to obtain the maximum height covered by the ball and then calculate the potential energy
u = initial velocity of the ball = 3 m/s
h = y = vertical distance covered by the ball = ?
v = final velocity of the ball at the maximum height = 0 m/s
g = acceleration due to gravity = -9.8 m/s²
v² = u² + 2ay
0 = 3² + 2(-9.8)(y)
19.6y = 9
y = (9/19.6)
y = 0.459 m
The potential energy the ball will have at the top of its motion = mgh
mgh = (10)(9.8)(0.459) = 45 J
Hope this Helps!!!
<span>We are using the formula: v = rω
Please consider that they have the same tangential velocity at their edges.
Therefore we can equate: r1 ω1 = r2 ω2
And re-arrange: ω1 / ω2 = r2 / r1</span>