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3 years ago

9. Complete the following statement:

Physics

1 answer:

mario62 [17]3 years ago

7 0

Answer:

E) the flow of energy due to a temperature difference.

Explanation:

Heat can be described as the flow of energy due to a temperature difference.

Which is expressed mathematically as;

H = MCΔT

Where;

H is the quantity of heat in a body, measured in Joules

M is the mass of the body, measured in kg

C is the specific heat capacity of the body, J/kg.K

ΔT is change in temperature or temperature difference.

So, heat energy in any system flows from a hotter region to a colder region due to temperature difference.

E) the flow of energy due to a temperature difference.

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A certain brand of hot dog cooker works by applying a potential difference of 120 V across opposite ends of a hot dog and allowi

Whitepunk [10]

Answer: 43s

Explanation:

The stored energy across a plate can be measured by calculating the electric charge and the potential difference. Also, the quantity of electricity can be measured by multiplying the current in the circuit with the time taken.

Given

Potential difference, V = 120 v

Current, I = 11.5 A

Energy, E = 59 kJ

Remember,

E = QV, so that

Q = E/V

Q = 59000/120

Q = 491.67 C

Q = IT

491.67 = 11.5*t

t = 491.67/11.5

t = 42.75s ~ 43s

Time taken to cook the 3 hot dogs simultaneously is 43s

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4 years ago

Which sizes influence the adhesive and rolling friction?

julsineya [31]

juju on that beat

Explanation:

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3 years ago

A 56 kg astronaut stands on a bathroom scale inside a rotating circular space station. The radius of the space station is 250 m.

Zielflug [23.3K]

Answer:

The speed of space station floor is 49.49 m/s.

Explanation:

Given that,

Mass of astronaut = 56 kg

Radius = 250 m

We need to calculate the speed of space station floor

Using centripetal force and newton's second law

$F=mg$

$\dfrac{mv^2}{r}=mg$

$\dfrac{v^2}{r}=g$

$v=\sqrt{rg}$

Where, v = speed of space station floor

r = radius

g = acceleration due to gravity

Put the value into the formula

$v=\sqrt{250\times9.8}$

$v=49.49\ m/s$

Hence, The speed of space station floor is 49.49 m/s.

6 0

3 years ago

Sam has been working to improve his muscular fitness. He jumps rope and trains with weights. What will most likely be the result

const2013 [10]

Increased Bone Density

4 0

4 years ago

Read 2 more answers

If you push a crate horizontally with 100 N across a 10 m factory floor and the friction between the crate and the floor is a st

erik [133]

Answer:

300 J

Explanation:

First of all, we need to calculate the net force acting on the crate, which is given by:

$F_{net} = F-F_f$

where

F = 100 N is the horizontal push

$F_f = 70 N$ is the force of friction

Substituting,

$F_{net}=100 - 70 = 30 N$

Now we can calculate the net work done on the crate:

$W=F_{net}d$

where

d = 10 m is the displacement

Substituting,

$W=(30)(10)=300 J$

According to the work-energy theorem, the kinetic energy gained by the crate is equal to the work done on it: therefore, the answer is 300 J.

4 0

3 years ago