Answer:
-v/2
Explanation:
Given that:
- Collides with the wall going through a sliding motion on on the plane smooth surface.
- Upon rebounding from the wall its kinetic energy becomes one-fourth of the initial kinetic energy before collision.
<u>We know, kinetic energy is given as:</u>
consider this to be the initial kinetic energy of the body.
<u>Now after collision:</u>
Considering that the mass of the body remains constant before and after collision.
Therefore the velocity of the body after collision will become half of the initial velocity but its direction is also reversed which can be denoted by a negative sign.
Answer:
The force required to begin to lift the pole from the end 'A' is 240 N
Explanation:
The given parameters for the pole AB are;
The length of the pole, l = 10.0 m
The weight of the pole, W = 600 N ↓
The distance of the center of gravity of the pole from the side 'A' = 4.0 m
Let '' represent the force required to begin to lift the pole from the end 'A' and let a force applied in the upwards direction be positive
For equilibrium, the sum of moment about the point 'B' = 0, therefore, taking moment about 'B', we have
× 10.0 m - W × 4.0 m = 0
∴ × 10.0 m = W × 4.0 m = 600 N × 4.0 m
× 10.0 m = 600 N × 4.0 m
∴ = 600 N × 4.0 m/(10.0 m) = 240 N
The force required to begin to lift the pole from the end 'A', = 240 N.
Answer:
A. Objects 1 and 2 will not move, and objects 3 and 4 will accelerate
upward.
Explanation:
A is correct as the weight in Objects 1, and 2 is greater than the person's push force; however it is on the ground meaning it is at it's stable state meaning the box couldn't be moved downwards anymore. And The newtons in 3 and 4 are the same
B is incorrect as Object 3 and 4 has a less Newton weight than newton force
C is incorrect as Object 1 and 2 has a greater Newton weight than newton force
D is incorrect as Object 1 and 2 wouldn't move downwards
Hope this helps!
Answer:
the kinetic energy of block will be equal to energy stored in spring ie 720 J
the speed of block will be 37.9 m/s
Explanation:
E = m v^2 / 2
v = sqrt (2 * E / m)
v = sqrt (2 * 720 J / 1 kg) = 37.9 m/s