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Savatey [412]
2 years ago
10

Algebra please help fast

Mathematics
2 answers:
Elis [28]2 years ago
7 0

Answer:

10/3

Step-by-step explanation:

1. Divide:

\frac{n+4}{6}=4

\frac{n+2}{3} =4

2. Subtract \frac{2}{3} from both sides of the equation

3. simplify

Answer: N = \frac{10}{3}

Artyom0805 [142]2 years ago
5 0

Answer:

n = 20

Step-by-step explanation:

\frac{n+4}{6} = 4

You need to get rid of the 6 in the denominator on the left hand side to make it easier to solve, so multiply both sides by 6. So you would get:

( \frac{n+4}{6} ) × 6 = 4 × 6

n+4 = 24

Then just rearrange for n by subtracting 4 on both sides.

n+4 = 24

n= 24-4

n=20

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Answer:

Step-by-step explanation:

-6.25x > -38 3/4

-6.25x > -155/4

Multiply by (-4)

25x > 155

divide by 25,

x > 155/25

x > 31/5

x > 6.2

8 0
3 years ago
A certain bank balance b is given by b= 100+d-w where d is deposits and w is withdrawls. What is the balance when d =100 and w=1
expeople1 [14]
You know that d = 100 and w = 125, so you plug that into the equation and solve as shown:
b= 100 + d - w
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3 years ago
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. What is the value of x in the equation –6 + x = –2?
Usimov [2.4K]
4 is the right answer
5 0
3 years ago
What is the area of this shape
alekssr [168]

Answer:

179 + 49+ 139 = 367

Step-by-step explanation:

6 0
3 years ago
What is the area of a regular hexagon (6 sides) whose
Ganezh [65]

Step-by-step explanation:

With reference to the regular hexagon, from the image above we can see that it is formed by six triangles whose sides are two circle's radii and the hexagon's side. The angle of each of these triangles' vertex that is in the circle center is equal to 360∘6=60∘ and so must be the two other angles formed with the triangle's base to each one of the radii: so these triangles are equilateral.

The apothem divides equally each one of the equilateral triangles in two right triangles whose sides are circle's radius, apothem and half of the hexagon's side. Since the apothem forms a right angle with the hexagon's side and since the hexagon's side forms 60∘ with a circle's radius with an endpoint in common with the hexagon's side, we can determine the side in this fashion:

tan60∘=opposed cathetusadjacent cathetus => √3=Apothemside2 => side=(2√3)Apothem

As already mentioned the area of the regular hexagon is formed by the area of 6 equilateral triangles (for each of these triangle's the base is a hexagon's side and the apothem functions as height) or:

Shexagon=6⋅S△=6(base)(height)2=3(2√3)Apothem⋅Apothem=(6√3)(Apothem)2

=> Shexagon=6×62√3=216

8 0
2 years ago
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