Answer:
moles of water were removed from the sample by the heating process
Explanation:
Given
Mass of the evaporating dish grams
Mass of the sample of hydrate grams
Mass of the sample and dish after heating grams
The weight of water removed through evaporation
grams
Weight of one mole of water grams
Number of moles of water in Grams of water is equal to
moles
The molarity of the NaOH solution is 0.03 M
We'll begin by calculating the mole of the KHP
Mole = mass /molar mass
Mole of KHP = 0.212 / 204.22
Mole of KHP = 0.001 mole
Next, we shall determine the molarity of the KHP solution
Molarity = mole / Volume
Molarity of KHP = 0.001 / 0.05
Molarity of KHP = 0.02 M
Finally , we shall determine the molarity of the NaOH solution
KHP + NaOH —> NaPK + H₂O
From the balanced equation above,
From the question given above, the following data were obtained:
MaVa / MbVb = nA / nB
(0.02 × 50) / (Mb × 35) = 1
1 / (Mb × 35) = 1
Cross multiply
Mb × 35 = 1
Divide both side by 35
Mb = 1 / 35
Mb = 0.03 M
Thus, the molarity of the NaOH solution is 0.03 M
Complete question:
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