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Ronch [10]
3 years ago
9

Unlike a prokaryotic bacteria cell, a virus, like the one in the image, A) has a lipid cell wall. B) has no genetic material. C)

cannot reproduce on its own. Eliminate D) does not contain any organic molecules.
Chemistry
2 answers:
I am Lyosha [343]3 years ago
4 0
The answer is C. The virus can't duplicate all alone. A virus is a natural specialist that repeats inside the cells of living hosts. At the point when contaminated by an infection, a host cell is compelled to create a large number of indistinguishable duplicates of the first infection at a remarkable rate.
Viktor [21]3 years ago
4 0

Answer:

the Answer is in the passage you just have to read trust me its there.

Explanation:

You might be interested in
The table shows the number of charged subatomic particles in an ion. Charge on Particle
katovenus [111]

Answer:

the answer is C) the iron will repel the substance because it has more electrons than protons

8 0
3 years ago
a sample of an unknown gas has a mass of 0.582g. it's volume is 21.3 mL a a temp of 100 degrees Celsius and a pressure of 754 mm
Zielflug [23.3K]

Answer:

Molar mass = 0.09 × 10⁴ g/mol

Explanation:

Given data:

Mass = 0.582 g

Volume = 21.3 mL

Temperature = 100°C

Pressure = 754 mmHg

Molar mass = ?

Solution:

(21.3 /1000 = 0.0213 L)

(100+273= 373 K)

(754/760 = 0.99 atm)

PV = nRT

n = PV/RT

n = 0.99 atm × 0.0213 L / 0.0821 atm. L. mol⁻¹. k⁻¹ × 373 K

n =0.02 mol/ 30.6

n = 6.5 × 10⁻⁴ mol

Molar mass = Mass/ number of moles

Molar mass = 0.582 g / 6.5 × 10⁻⁴ mol

Molar mass = 0.09 × 10⁴ g/mol

6 0
3 years ago
The molar mass of NH3 is 17.03 g/mol. The molar mass of H2 is 2.0158 g/mol. In a particular reaction, 0.575 g of NH3 forms. What
vivado [14]
The answer 
the general for of the equation of reaction is 
N2        +     3 H2 ------------   2NH3
1mol            3mole                2 mole
                    nH2                   nNH3
(nX means number of mole of X)

according to the law of proportion
3 / nH2  =  2 / nNH3  (E)

nNH3 = m NH3  / 17.03 , and m NH3 = <span>0.575 g
consequently </span>nNH3 =  0.575 g  / 17.03 = 0.03 mol

by considering (E)  3 / nH2  =  2 / 0.03 = 66.66, and nH2  = 3 / 66.66 =0.045

finally we can write 

mH2 = nH2 x 2.0158 =0.045 x 2.0158 = 0.09 g
6 0
3 years ago
Which of the following gives the net ionic reaction for the reaction used in this experiment?
CaHeK987 [17]

Answer: Option (d) is the correct answer.

Explanation:

The given reaction will be as follows.

       Ba(OH)_{2}(aq) + H_{2}SO_{4}(aq) \rightarrow BaSO_{4}(s) + 2H_{2}O(l)

In the ionic form, the equation will be as follows.

           Ba^{2+}(aq) + SO^{2-}_{4}(aq) \rightarrow BaSO_{4}(s) ........ (1)

           H^{+}(aq) + OH^{-}(aq) \rightarrow H_{2}O(l) ............ (2)

Hence, for the net ionic equation we need to add both equation (1) and (2). Therefore, the net ionic equation will be as follows.

     Ba^{2+}(aq) + SO^{2-}_{4}(aq) + H^{+}(aq) + OH^{-}(aq) \rightarrow BaSO_{4}(s) + H_{2}O(l)        

Now, balancing the atoms on both the sides we get the net ionic equation as follows.

         Ba^{2+}(aq) + SO^{2-}_{4}(aq) + 2H^{+}(aq) + 2OH^{-}(aq) \rightarrow BaSO_{4}(s) + 2H_{2}O(l)          

5 0
3 years ago
A reaction A ( aq ) + B ( aq ) − ⇀ ↽ − C ( aq ) has a standard free‑energy change of − 5.24 kJ / mol at 25 °C. What are the conc
GalinKa [24]

Answer:

[A]_{eq}=0.11M

[B]_{eq}=0.21M

[C]_{eq}=0.19M

Explanation:

Hello,

In this case, for the given reaction, based on the information about its Gibbs free energy, we obtain the equilibrium constant as shown below:

Kc=exp(-\frac{\Delta _RG }{RT} )=exp[-\frac{-5240J/mol }{(8.314J/mol*K)(298.15K)} ]=8.28

Now, by means of the law of mass action in terms of the undergoing change x due to the chemical reaction, we obtain:

Kc=\frac{x}{(0.30-x)(0.40-x)} =8.28

For which the solution for x by solver is:

x=0.19M

Thus, the equilibrium concentrations result:

[A]_{eq}=0.3M-0.19M=0.11M

[B]_{eq}=0.4M-0.19M=0.21M

[C]_{eq}=0.19M

Best regards.

5 0
3 years ago
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