This is actually science but anyways my teacher didn't explain much can someone help?
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Answer:
Check explanation
Explanation:.
NOTE: kindly check for attached file/picture for the graph.
From the graph of absorbance against concentration from the question. We can see that the 0.3 mark absorbance is equivalent to 0.15 M. So, the concentration of CuSO4 is 0.15 M.
The concentration can also be calculated using the Beer-lambert equation for absorbance. The equation is given below;
A= ɛ×C×l --------------------------------------------------------------------------------------(1).
Where A= absorbance, ɛ= molar absorptivity, C= concentration and l= length.
Therefore, the concentration,C will now be; C= A/ ɛ×l. -------------------------------------------------------------------------(2).
Assuming the length,l is 1cm.
Hence, C= 0.300/ ɛ×1.
C= (0.300/ ɛ) M.
