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3 years ago

How many solutions exist for the system of equations below?

Mathematics

2 answers:

Vaselesa [24]3 years ago

6 0

Answer:

Step-by-step explanation:

timurjin [86]3 years ago

5 0

Answer:

0 (None) solutions

Step-by-step explanation:

This Linear System has no Solution. It means that mathematically speaking, whatever value inserted for x, or y this will not result in an equality, i.e. we'll always have a false value. Like this:

$\left\{\begin{matrix}3x+y=18&&\\3x+y=16&&\end{matrix}\right.\Rightarrow 3x+(16-3x)=18\Rightarrow 0x=-2$

FALSE Because $0x\neq-2$ then This Linear System does not have solution.

Geometrically, both equations are parallel lines, so they do not have any common point, i.e. solution. Notice they both have the same slope. Check the graph below.

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3 years ago

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2 years ago

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3 years ago

A closed box with a square base is to have a volume of 85. 75 cm^3. the material for the top and bottom of the box costs $3.00

tiny-mole [99]

We can create two equations here:

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85.75 = s^2 h

(2) Cost = 3 * area of square + 1.5 * area of side box

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From (1), we get:

h = 85.75 / s^2

Combining this with (2):

C = 3 s^2 + 1.5 s (85.75 / s^2)

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dC/ds = 6s – 128.625 / s^2 = 0

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6s^3 – 128.625 = 0

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So h is:

h = 85.75 / s^2 = 85.75 / (2.78)^2

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So the dimensions are 2.78 cm x 2.78 cm x 11.10 cm

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C = 3 (2.78)^2 + 1.5 (2.78) (11.10)

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