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3 years ago

How many solutions exist for the system of equations below?

Mathematics

2 answers:

Vaselesa [24]3 years ago

6 0

Answer:

Step-by-step explanation:

timurjin [86]3 years ago

5 0

Answer:

0 (None) solutions

Step-by-step explanation:

This Linear System has no Solution. It means that mathematically speaking, whatever value inserted for x, or y this will not result in an equality, i.e. we'll always have a false value. Like this:

$\left\{\begin{matrix}3x+y=18&&\\3x+y=16&&\end{matrix}\right.\Rightarrow 3x+(16-3x)=18\Rightarrow 0x=-2$

FALSE Because $0x\neq-2$ then This Linear System does not have solution.

Geometrically, both equations are parallel lines, so they do not have any common point, i.e. solution. Notice they both have the same slope. Check the graph below.

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The future value of a certain money market account with a fixed interest rate of

rosijanka [135]

Answer:

D = $8637.45

Step-by-step explanation:

Rate = 3.65% = 0.0365

Principal = 5000

Time (t) = 15 years

N = 12 (since its compounded monthly)

Compound interest (A) = P(1 + r/n)^nt

A = 5000(1 + 0.0365 / 12)^15*12

A = 5000(1 + 0.00304)¹⁸⁰

A = 5000(1.00304)¹⁸⁰

A = 5000 * 1.7269

A = 8634.86

The investment would worth $8634.86

Note: the final answer may vary slightly from the answer in the options due to ± from approximation

3 0

3 years ago

A particular state has elected both a governor and a senator. Let A be the event that a randomly selected voter has a favorable

Elodia [21]

Answer:

Step-by-step explanation:

Given that A be the event that a randomly selected voter has a favorable view of a certain party’s senatorial candidate, and let B be the corresponding event for that party’s gubernatorial candidate.

Suppose that

P(A′) = .44, P(B′) = .57, and P(A ⋃ B) = .68

From the above we can find out

P(A) = $1-0.44 = 0.56$

P(B) = $1-0.57 = 0.43$

P(AUB) = 0.68 =

$0.56+0.43-P(A\bigcap B)\\P(A\bigcap B)=0.30$

a) the probability that a randomly selected voter has a favorable view of both candidates=P(AB) = 0.30

b) the probability that a randomly selected voter has a favorable view of exactly one of these candidates

= P(A)-P(AB)+P(B)-P(AB)

$=0.99-0.30-0.30\\=0.39$

c) the probability that a randomly selected voter has an unfavorable view of at least one of these candidates

=P(A'UB') = P(AB)'

= $1-0.30\\=0.70$

3 0

3 years ago

Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)

babunello [35]

$\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k$

We want to find $f(x,y,z)$ such that $\nabla f=\vec F$ . This means

$\dfrac{\partial f}{\partial x}=x^2+y$

$\dfrac{\partial f}{\partial y}=y^2+x$

$\dfrac{\partial f}{\partial z}=ze^z$

Integrating both sides of the latter equation with respect to $z$ tells us

$f(x,y,z)=e^z(z-1)+g(x,y)$

and differentiating with respect to $x$ gives

$x^2+y=\dfrac{\partial g}{\partial x}$

Integrating both sides with respect to $x$ gives

$g(x,y)=\dfrac{x^3}3+xy+h(y)$

Then

$f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)$

and differentiating both sides with respect to $y$ gives

$y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C$

So the scalar potential function is

$\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}$

By the fundamental theorem of calculus, the work done by $\vec F$ along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it $L$ ) in part (a) is

$\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}$

and $\vec F$ does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them $L_1$ and $L_2$ ) of the given path. Using the fundamental theorem makes this trivial: