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3 years ago

Factor x2 -4x +4 find the answer.

Mathematics

1 answer:

Dmitriy789 [7]3 years ago

5 0

This would be (x - 2)^2 i hope this helps sorry if incorrect!

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33.2g of sugar is needed to make 4 cakes. How much sugar is needed for 6 cakes?

irinina [24]

33.2g/4 cakes = 8.3g/cake

8.3g*6 cakes = 49.8grams

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3 years ago

Read 2 more answers

Complete each trinomial such that it can be rewritten in the form

lukranit [14]

Answer:

Step-by-step explanation:

1.5x^2+6x+.... so that it can be rewritten in the form a(x+b)^2

Let .... be C

1.5x^2+6x+C

=1.5(x^2+4x+(C/1.5))

Compare above with 1.5(x+2)^2 = 1.5(x^2+4x+4)

C/1.5=4

C=6

So the expression should be 1.5x^2+6x+6

It can be rewritten to 1.5(x+2)^2

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2 years ago

What is the area of a cylinder

Licemer1 [7]

A cylinder's volume is =

π r² h,

and its surface area is =

2π r h + 2π r².

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2 years ago

If 7/x + 8/y = 2; 2/x + 12/y = 20, then x = ?

kvv77 [185]

Answer:

<h3><u>Given Question</u></h3>

$\sf \: \dfrac{7}{x} + \dfrac{8}{y} = 2, \: \dfrac{2}{x} + \dfrac{12}{y} = 20, \: then \: x \: = \:$

$\green{\large\underline{\sf{Solution-}}}$

Given pair of equations are

$\rm :\longmapsto\:\dfrac{7}{x} + \dfrac{8}{y} = 2 - - - - (1)$

and

$\rm :\longmapsto\:\dfrac{2}{x} + \dfrac{12}{y} = 20$

On dividing by 2, we get

$\rm :\longmapsto\:\dfrac{1}{x} + \dfrac{6}{y} = 10 - - - - (2)$

On multiply equation (1) by 3 and (2) by 4, we get

$\rm :\longmapsto\:\dfrac{21}{x} + \dfrac{24}{y} = 6 - - - - (3)$

and

$\rm :\longmapsto\:\dfrac{4}{x} + \dfrac{24}{y} = 40 - - - - (4)$

On Subtracting equation (3) from (4), we get

$\rm :\longmapsto\: - \dfrac{17}{x} = 34$

$\rm :\longmapsto\: - \dfrac{17}{34} = x$

$\bf\implies \:x \: = \: - \: \dfrac{1}{2}$

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<h3><u>Concept Used :- </u></h3>

There are 4 methods to solve this type of pair of linear equations.

1. Method of Substitution

2. Method of Eliminations

3. Method of Cross Multiplication

4. Graphical Method

We prefer here Method of Eliminations :-

To solve systems using elimination, follow this procedure:

<h3><u>The Elimination Method</u></h3>

Step 1: Multiply each equation by a suitable number so that the two equations have the same leading coefficient.

Step 2: Subtract the second equation from the first to eliminate one variable

Step 3: Solve this new equation for other variable.

Step 4: Substitute the value of variable thus evaluated into either Equation 1 or Equation 2 and get the value other variable.

4 0

3 years ago

HELP PLS ITS IREADY MATH IM STUCK

Jobisdone [24]

I think left bottom. Have a nice day

4 0

3 years ago