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4 years ago

Evaluate the algebraic expression for the given values of x=3 and y=4 . 7x−2y−1 =

Mathematics

2 answers:

STALIN [3.7K]4 years ago

8 0

The answer for this question is 12

Triss [41]4 years ago

5 0

Answer:

Step-by-step explanation:

Substitute in the values

7x = 7*3 = 21

-2y = - 2 * 4 =. - 8

Then there's - 1 aswell

Put it all together and you get 21 - 8 - 1

Whivh equals to 12

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motikmotik

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3 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

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3 years ago

I will mark you brainiest if you can answer this

Svet_ta [14]

The answer should be B bc the point is at 1 and it rises 2 and runs 3 to the left so it’s negative

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3 years ago

If f(x) = f(x)g(x), where f and g have derivatives of all orders, show that f'' = f ''g + 2f 'g' + fg''.

Nadya [2.5K]

Differentiating once, we have

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Differentiating again,

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as needed.

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3 years ago

The congruent sides of an isosceles triangle are called ____, and the third side is called the _____.

In-s [12.5K]

Answer:

Step-by-step explanation:

Congruent sides are called legs.

Third side is called the base.

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3 years ago

Evaluate the algebraic expression for the given values of x=3 and y=4 . ​ ​ 7x−2y−1 =

Evaluate the algebraic expression for the given values of x=3 and y=4 . 7x−2y−1 =