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dimulka [17.4K]
2 years ago
10

Use the following, balanced equation for the question below: 2Al(s) + 3CuCl2(aq) → 3Cu(s) + 2AlCl3(aq) How many moles of copper

metal will be produced from 10.0 moles of aluminum metal? 10.0 moles of copper 15.0 moles of copper 20.0 moles of copper 30.0 moles of copper
Chemistry
1 answer:
Galina-37 [17]2 years ago
3 0

Answer: 15.0 moles of copper

Explanation:

The balanced chemical equation is:-

2Al(s)+3CuCl_2(aq)\rightarrow 3Cu(s)+2AlCl_3(aq)

Aluminium is the limiting reagent as it limits the formation of product.

According to stoichiometry:-

2 moles of aluminium produce = 3 moles of copper

10 moles of aluminium produce =\frac{3}{2}\times 10=15 moles of copper.

Thus 15 moles of copper will be produced from 10 moles of aluminium.

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Manganese forms several oxides when combined with oxygen. One of the oxides (Oxide 1) contains 63.2% of Mn and another oxide (Ox
Nina [5.8K]

Explanation:

Defining law of definite proportions, it states that when two elements form more than one compound, the ratios of the masses of the second element which combine with a fixed mass of the first element will always be ratios of small whole numbers.

A. One of the oxides (Oxide 1) contains 63.2% of Mn.

Mass of the oxide = 100g

Mass of Mn = 63.2 g

Mass of O = 100 - 63.2

= 36.8 g

Ratio of Mn to O = 63.2/36.8

= 1.72

Another oxide (Oxide 2) contains 77.5% Mn.

Mass of oxide = 100 g

Mass of Mn = 77.5 g

Mass of O = 100 - 77.5

= 22.5 g

Ratio of Mn to O = 77.5/22.5

= 3.44

Therefore, the ratio of the masses of Mn and O in Oxide 1 and Oxide 2 is in the ratio 1.72 : 3.44, which is also 1 : 2. So the law of multiple proportions is obeyed.

B.

Oxide 1

Mass of Mn per 1 g of O = mass of Mn/mass of O

= 77.5/22.5

= 3.44 g/g of Oxygen.

Oxide 2

Mass of Mn per 1 g of O = mass of Mn/mass of O

= 77.5/22.5

= 3.44 g/g of Oxygen.

3 0
3 years ago
The process by which hot and cold air are transferred in the atmosphere is
Elan Coil [88]

Convection: the movement caused within a fluid by the tendency of hotter and therefore less dense material to rise, and colder, denser material to sink under the influence of gravity, which consequently results in transfer of heat.

hope that helps :)

3 0
3 years ago
The acid dissociation constant Ka of boric acid (H3BO3) is 5.8 times 10^-10. Calculate the pH of a 4.4 M solution of boric acid.
madam [21]

Answer: The pH of a 4.4 M solution of boric acid is 4.3

Explanation:

H_3BO_3\rightarrow H^+H_2BO_3^-

at t=0  cM              0             0

at eqm c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 4.4 M and \alpha = ?

K_a=5.8\times 10^{-10}

Putting in the values we get:

5.8\times 10^{-10}=\frac{(4.4\times \alpha)^2}{(4.4-4.4\times \alpha)}

(\alpha)=0.000011

[H^+]=c\times \alpha

[H^+]=4.4\times 0.000011=4.8\times 10^{-5}M

Also pH=-log[H^+]

pH=-log[4.8\times 10^{-5}]=4.3

Thus pH of a 4.4 M H_3BO_3 solution is 4.3

3 0
3 years ago
_Cl2 + _NaBr → _NaCl + _Br2<br><br> Answer: 1,2,2,1
nlexa [21]
1 2 2 1 is the answer so u are correct
4 0
3 years ago
A sample of helium gas is in a sealed rigid container. What occurs as the temperature of the sample is increased
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The electrons will move more rapidly resulting in a higher pressure even at a consistent volume
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