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Elis [28]
3 years ago
8

How to find 17.3205 to the nearest 0.1 meter?

Mathematics
1 answer:
mr Goodwill [35]3 years ago
4 0
See how if the number (1-4 u would round down, 5-9 u round up) u would look at the place value it asks then look at the one next to it and see if u round up of down so it would be 17.3
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6x+2(x+4)<2x+20 solve for inequality
8_murik_8 [283]

The problem to solve is:

6x+2(x+4)‹2x+20

First, let's work on the left hand side of your inequality, the 6x+2(x+4)

This means, for instance, to see if it can be simplified at all.

Multiply x and 6

Multiply x and 1

The x just gets copied along.

The answer is x

x

6*x evaluates to 6x

x+4 evaluates to x+4

Multiply 2 by x+4

we multiply 2 by each term in x+4 term by term.

This is the distributive property of multiplication.

Multiply 2 and x

Multiply 1 and x

The x just gets copied along.

x

2 × x = 2x

Multiply 2 and 4

1

2 × 4 = 8

2*(x+4) evaluates to 2x+8

6x + 2x = 8x

The answer is 8x+8

6*x+2*(x+4) evaluates to 8x+8

So, all-in-all, the left hand side of your inequality can be written as: 8x+8

Now, let's work on the right hand side of your inequality, the 2x+20

Multiply x and 2

Multiply x and 1

The x just gets copied along.

The answer is x

x

2*x evaluates to 2x

2*x+20 evaluates to 2x+20

The right hand side of your inequality can be written as: 2x+20

So with these (any) simplifications, the inequality we'll set out to solve is:

8x+8 ‹ 2x+20

Move the 8 to the right hand side by subtracting 8 from both sides, like this:

From the left hand side:

8 - 8 = 0

The answer is 8x

From the right hand side:

20 - 8 = 12

The answer is 12+2x

Now, the inequality reads:

8x ‹ 12+2x

Move the 2x to the left hand side by subtracting 2x from both sides, like this:

From the left hand side:

8x - 2x = 6x

The answer is 6x

From the right hand side:

2x - 2x = 0

The answer is 12

Now, the inequality reads:

6x ‹ 12

To isolate the x, we have to divide both sides of the inequality by the other "stuff" (variables or coefficients)

around the x on the left side of the inequality.

The last step is to divide both sides of the inequality by 6 like this:

To divide x by 1

The x just gets copied along in the numerator.

The answer is x

6x ÷ 6 = x

12 ÷ 6 = 2

The solution to your inequality is:

x ‹ 2

So, your solution is:

x must be less than 2The problem to solve is:

6x+2(x+4)‹2x+20

First, let's work on the left hand side of your inequality, the 6x+2(x+4)

This means, for instance, to see if it can be simplified at all.

Multiply x and 6

Multiply x and 1

The x just gets copied along.

The answer is x

x

6*x evaluates to 6x

x+4 evaluates to x+4

Multiply 2 by x+4

we multiply 2 by each term in x+4 term by term.

This is the distributive property of multiplication.

Multiply 2 and x

Multiply 1 and x

The x just gets copied along.

x

2 × x = 2x

Multiply 2 and 4

1

2 × 4 = 8

2*(x+4) evaluates to 2x+8

6x + 2x = 8x

The answer is 8x+8

6*x+2*(x+4) evaluates to 8x+8

So, all-in-all, the left hand side of your inequality can be written as: 8x+8

Now, let's work on the right hand side of your inequality, the 2x+20

Multiply x and 2

Multiply x and 1

The x just gets copied along.

The answer is x

x

2*x evaluates to 2x

2*x+20 evaluates to 2x+20

The right hand side of your inequality can be written as: 2x+20

So with these (any) simplifications, the inequality we'll set out to solve is:

8x+8 ‹ 2x+20

Move the 8 to the right hand side by subtracting 8 from both sides, like this:

From the left hand side:

8 - 8 = 0

The answer is 8x

From the right hand side:

20 - 8 = 12

The answer is 12+2x

Now, the inequality reads:

8x ‹ 12+2x

Move the 2x to the left hand side by subtracting 2x from both sides, like this:

From the left hand side:

8x - 2x = 6x

The answer is 6x

From the right hand side:

2x - 2x = 0

The answer is 12

Now, the inequality reads:

6x ‹ 12

To isolate the x, we have to divide both sides of the inequality by the other "stuff" (variables or coefficients)

around the x on the left side of the inequality.

The last step is to divide both sides of the inequality by 6 like this:

To divide x by 1

The x just gets copied along in the numerator.

The answer is x

6x ÷ 6 = x

12 ÷ 6 = 2

The solution to your inequality is:

x ‹ 2

So, your solution is:

x must be less than 2

7 0
3 years ago
Which formula can be used to describe the sequence below? –8, –5, –2, 1, 4, ...
makvit [3.9K]

Answer:

an = -8 +3(n-1)

an = -11 +3n

f(n) = -11 +3n

Step-by-step explanation:

–8, –5, –2, 1, 4, ...

This is an arithmetic sequence.

We are increasing by 3 each time

-8 +3 = -5

-5+3 = -2

-2 +3 = 1

The common difference is 3

The formula for an arithmetic sequence is

an = a1 +d (n-1)

an = -8 +3(n-1)

an = -8 +3n -3

an = -11 +3n

The nth term is -11 +3n

f(n) = -11 +3n

3 0
4 years ago
Read 2 more answers
HELP
babymother [125]

It's a isosceles right angled triangle

  • LJ=17
  • KL=10

\\ \sf{:}\Rrightarrow JK^2=17^2+10^2

\\ \sf{:}\Rrightarrow JK^2=289+100

\\ \sf{:}\Rrightarrow JK^2=389

\\ \sf{:}\Rrightarrow JK=19.72

4 0
3 years ago
When you read carefully in order to determine the meaning of a challenging word,you are
aivan3 [116]

Answer: Using context clues

Step-by-step explanation:

5 0
4 years ago
I own a large truck, and my neighbor owns four small trucks that are all identical. My truck can carry a load of at least 600 po
Sloan [31]

Answer:

The load the large truck can carry  is 2400 pounds

Step-by-step explanation:

Let the load the large truck can carry  = X

Let the  load each of the four trucks owned by the neighbor can carry = Y

The given parameters are;

The load the large truck can carry X = 600 + Y......(1)

The number trucks owned by the neighbor = 4

The load the large truck can carry X ≤ 1/3 × 4 × Y

Therefore, X ≤ 4/3 × Y

At maximum capacity, we have;

X = 4/3 × Y

Substituting the value of X into equation (1), we have;

4/3 × Y = 600 + Y

600 = 4/3 × Y - Y = 1/3·Y

Y = 3 × 300 = 1800 pounds

Y =  = 1800 pounds

Therefore, the load the neighbors truck can carry = 1800 pounds

X = 600 + Y gives;

X = 600 + 1800 = 2400 pounds

∴ The load the large truck can carry  = 2400 pounds

5 0
3 years ago
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