Answer:
The answer to your question are letters A, C and D.
Step-by-step explanation:
To factor this polynomial we need to look for the common factor of the three terms.
To find it, get the greatest common factor
140 28 14 2
70 14 7 2
35 7 7 5
7 7 7 7
1 1 1
Greatest common factor = 2 x 7 = 14
Factor the polynomial
140c + 28 - 14a = 14 ( 10c + 2 - a)
Factor only 7 7(20c + 4 - 2a)
Factor only 2 2 (70c + 14 - 7a)
Answer:
PQ=30
Step-by-step explanation:
Knowing that the segment has 3 parts that are 3:1:1 and sum up to 50, you could find how much 1 would equal by finding the total in relation to the ratio (doing 3+1+1) which gets you 5 parts. Then you can divide the total (50) by 5 to figure out how much one part would equal (10). Now, since you know that 1 part is equal to 10 and that PQ is 3 parts, you can find that PQ is equal to 3x10, or 30.
A is the answer to your question
![\dfrac\partial{\partial y}\left[e^{2y}-y\cos xy\right]=2e^{2y}-\cos xy+xy\sin xy](https://tex.z-dn.net/?f=%5Cdfrac%5Cpartial%7B%5Cpartial%20y%7D%5Cleft%5Be%5E%7B2y%7D-y%5Ccos%20xy%5Cright%5D%3D2e%5E%7B2y%7D-%5Ccos%20xy%2Bxy%5Csin%20xy)
![\dfrac\partial{\partial x}\left[2xe^{2y}-y\cos xy+2y\right]=2e^{2y}+y\sin xy](https://tex.z-dn.net/?f=%5Cdfrac%5Cpartial%7B%5Cpartial%20x%7D%5Cleft%5B2xe%5E%7B2y%7D-y%5Ccos%20xy%2B2y%5Cright%5D%3D2e%5E%7B2y%7D%2By%5Csin%20xy)
The partial derivatives are not equal, so the equation is not exact.
