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cestrela7 [59]
2 years ago
7

7/12 of the books in simone's library are. 3/12 of the books in simone's library are historical fiction. what fraction of the bo

oks in simone's library are either mysteries or historical fiction
Mathematics
1 answer:
vova2212 [387]2 years ago
6 0

Answer:

16%
2/12

Step-by-step explanation:

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What is the product of 6 1/2 and <br>9 1/4​
Simora [160]

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▹ Answer

<em>60 1/8 or 481/8</em>

<em> </em>

▹ Step-by-Step Explanation

6 \frac{1}{2} * 9 \frac{1}{4} \\\\= \frac{13}{2} * \frac{37}{4} \\\\= \frac{481}{8} \\\\= 60\frac{1}{8} or \frac{481}{8}

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

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8 0
3 years ago
Read 2 more answers
I give brainliest please help
Furkat [3]
It’s the 31 hope this helps you
3 0
3 years ago
Please I will give brainliest !!!!!
Svetlanka [38]
The answer is option 2,

2x10^10
8 0
3 years ago
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The designer sketched a model of the pond. The model drawing had a circumference of 24 inches. What is the AREA of the model she
Delicious77 [7]

Answer:

Area of model pond = 45.6 inch² (Approx.)

Step-by-step explanation:

Given:

Circumference of circular pond = 24 inches

Find:

Area of model pond

Computation:

Circumference of circle = 2πr

Circumference of circular pond = 2πr

24 = 2[22/7][r]

Radius r = [24 x 7] / [2 x 22]

Radius r = 3.81 inch (Approx.)

Area of circle = πr²

Area of model pond = πr²

Area of model pond = (22/7)(3.81)²

Area of model pond = [3.1428][14.5161]

Area of model pond = 45.6 inch² (Approx.)

6 0
3 years ago
Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 90.5 N , Jill pul
Radda [10]

Answer:

Fn= 174.9 N : Magnitude of the net force the people exert on the donkey.

Step-by-step explanation:

We find the components of the forces in x-y-z

Force of  Jack in z   =F₁z=90.5 N in direction (+z)

Force of  Jill  in x     = F₂x= -82.3*cos45°= - 58.19 N (-x)

Force of  Jill  in y     =F₂y=-82.3*sin45°=   + 58.19 N (+y)

Force of  Jane  in x  =F₃x=125*cos45°=   + 88.4 N (+x)

Force of  Jane  in y   =F₃y=125*sin45°=   + 88.4  N (+y)

Calculating of the components of the net force the people exert on the donkey.

Fnx= F₂x+F₃x=( - 58.19+ 88.4 )N=30.2N (+x)

Fny= F₂y+F₃y=( 58.19+88.4 ) = 146.59 N (+y)

Fnz =F₁z=90.5 N  (+z)

Calculating of the magnitude of the net force the people exert on the donkey.

F_{n} =\sqrt{(F_{nx})^{2}+(F_{ny}) ^{2} +(F_{nz}) ^{2}   }

F_{n} =\sqrt{(30.2)^{2}+( 146.59) ^{2} +(90.5) ^{2}   }

F_{n} = 174.9 N

7 0
3 years ago
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