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const2013 [10]
2 years ago
12

What are the roots of the polynomial equation

Mathematics
1 answer:
rosijanka [135]2 years ago
7 0

Answer:

-4 or -3

Step-by-step explanation:

Calculate the determinant:

D = b^2 - 4ac = 49 - 48 = 1

Apply the formula:

x = (-b +- sqrt(D))/2a = (-7 +- 1)/2 = -4 or -3

You might be interested in
F(x)=4x-5, find f(-2)
GenaCL600 [577]

Answer:

The answer is -13.

Step-by-step explanation:

=4×(-2)-5

=-8-5

=-13

The value of (-2) is -13.

4 0
3 years ago
If f(x) =ax+b ,f(-3)=-4 and f(3)=2, find the value of a and b please help​
hichkok12 [17]

Answer:

a = 1

b = -1

Step-by-step explanation:

First, let's make equations out of those given f(x)'s

-4 = -3a + b

2 = 3a + b

We can use elimination method to get rid of the a real quick

-4 = b

2 = b

Add those together

-2 = 2b

Divide both sides by 2

-2/2 = 2b/2

b = -1

Plug in the new b in one of the original equations; I'm gonna use the bottom one

2 = 3a - 1

+ 1        + 1

3 = 3a

3/3 = 3a/3

a = 1

4 0
2 years ago
Please answer 25 points!
Alekssandra [29.7K]

Answer:

-3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find 2004-04-02-04-00_files/i0340000.jpg. Round the answer to the nearest tenth.
lesya692 [45]

<span>The problem is to calculate the angles of the triangle. However, it is not clear which angle you have to calculate, so we are going to calculate all of them
</span>
we know that
Applying the law of cosines
c²=a²+b²-2*a*b*cos C------> cos C=[a²+b²-c²]/[2*a*b]
a=12.5
b=15
c=11
so
 cos C=[a²+b²-c²]/[2*a*b]--->  cos C=[12.5²+15²-11²]/[2*12.5*15]
cos C=0.694------------> C=arc cos (0.694)-----> C=46.05°-----> C=46.1°

applying the law of sines calculate angle B
15 sin B=11/sin 46.1-----> 15*sin 46.1=11*sin B----> sin B=15*sin 46.1/11
 sin B=15*sin 46.1/11-----> sin B=0.9826----> B=arc sin (0.9826)
B=79.3°

calculate angle A
A+B+C=180------> A=180-B-C-----> A=180-79.3-46.1----> A=54.6°

the angles of the triangle are
A=54.6°
B=79.3°
C=46.1°
7 0
3 years ago
stion 1 OT 5A researcher recorded the number of swans and the number of ducks in a lake every month. Function s represents the n
Anon25 [30]

Given functions are

s(n)=2(1.1)^n+5_{}d(n)=4(1.08)^n+3

The total number of ducks and swans in the lake after n months can be determined by adding the functions s(n) and d(n).

t(n)=s(n)+d(n)

t(n)=(2(1.1)^n^{}+5)+(4(1.08)^n+3)

t(n)=2(1.1)^n+5+4(1.08)^n+3

t(n)=2(1.1)^n+4(1.08)^n+5+3

t(n)=2(1.1)^n+4(1.08)^n+8

Taking 2 as common, we get

t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack

Hence The total number of ducks and swans in the lake after n months is

t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack

8 0
1 year ago
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