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2 years ago

What are the roots of the polynomial equation

Mathematics

1 answer:

rosijanka [135]2 years ago

7 0

Answer:

-4 or -3

Step-by-step explanation:

Calculate the determinant:

D = b^2 - 4ac = 49 - 48 = 1

Apply the formula:

x = (-b +- sqrt(D))/2a = (-7 +- 1)/2 = -4 or -3

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Please help thanks ❗

mojhsa [17]

Answer:

The Two Column Proof is given below.

Step-by-step explanation:

Given:

$\overline{MP} \cong \overline{MN}$

$\overline{PO} \cong \overline{NO}$

To Prove:

∠ P ≅ ∠ N

Proof:

In Δ MPO and Δ MNO

STATEMENT REASONS

1. MP ≅ MN 1. Given

2. PO ≅ NO 2. Given

3. MO ≅ MO 3. Reflexive property

4. ΔMPO ≅ ΔMNO 4. Side-Side-Side congruence test}

5. ∠MPO ≅∠MNO 5. Corresponding parts of congruent Triangles

i.e ∠ P ≅ ∠ N ..................Proved

3 0

3 years ago

Helpppppppppppppppppp

topjm [15]

Answer:

Step-by-step explanation:

The question has no division answer. That makes C and D incorrect.

A for some reason is backwards. It makes no sense to use that. You are left with B. The reason A or B is correct is that the burn of calories must get larger with an increase in hours.

7 0

3 years ago

Can someone please help me on number 16-ABC

melomori [17]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the inequality

-2x < 10

-6 < -2x

<u>Part a) Is x = 0 a solution to both inequalities</u>

FOR -2x < 10

substituting x = 0 in -2x < 10

-2x < 10

-3(0) < 10

0 < 10

TRUE!

Thus, x = 0 satisfies the inequality -2x < 10.

∴ x = 0 is the solution to the inequality -2x < 10.

FOR -6 < -2x

substituting x = 0 in -6 < -2x

-6 < -2x

-6 < -2(0)

-6 < 0

TRUE!

Thus, x = 0 satisfies the inequality -6 < -2x

∴ x = 0 is the solution to the inequality -6 < -2x

Conclusion:

x = 0 is a solution to both inequalites.

<u>Part b) Is x = 4 a solution to both inequalities</u>

FOR -2x < 10

substituting x = 4 in -2x < 10

-2x < 10

-3(4) < 10

-12 < 10

TRUE!

Thus, x = 4 satisfies the inequality -2x < 10.

∴ x = 4 is the solution to the inequality -2x < 10.

FOR -6 < -2x

substituting x = 4 in -6 < -2x

-6 < -2x

-6 < -2(4)

-6 < -8

FALSE!

Thus, x = 4 does not satisfiy the inequality -6 < -2x

∴ x = 4 is the NOT a solution to the inequality -6 < -2x.

Conclusion:

x = 4 is NOT a solution to both inequalites.

Part c) Find another value of x that is a solution to both inequalities.

<u>solving -2x < 10</u>

$-2x\:$

Multiply both sides by -1 (reverses the inequality)

$\left(-2x\right)\left(-1\right)>10\left(-1\right)$

Simplify

$2x>-10$

Divide both sides by 2

$\frac{2x}{2}>\frac{-10}{2}$

$x>-5$

$-2x-5\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-5,\:\infty \:\right)\end{bmatrix}$

<u>solving -6 < -2x</u>

-6 < -2x

switch sides

$-2x>-6$

Multiply both sides by -1 (reverses the inequality)

$\left(-2x\right)\left(-1\right)$

Simplify

$2x$

Divide both sides by 2

$\frac{2x}{2}$

$x$

$-6$

Thus, the two intervals:

$\left(-\infty \:,\:3\right)$

$\left(-5,\:\infty \:\right)$

The intersection of these two intervals would be the solution to both inequalities.

$\left(-\infty \:,\:3\right)$ and $\left(-5,\:\infty \:\right)$

As x = 1 is included in both intervals.

so x = 1 would be another solution common to both inequalities.

<h3>SUBSTITUTING x = 1</h3>

FOR -2x < 10

substituting x = 1 in -2x < 10

-2x < 10

-3(1) < 10

-3 < 10

TRUE!

Thus, x = 1 satisfies the inequality -2x < 10.

∴ x = 1 is the solution to the inequality -2x < 10.

FOR -6 < -2x

substituting x = 1 in -6 < -2x

-6 < -2x

-6 < -2(1)

-6 < -2

TRUE!

Thus, x = 1 satisfies the inequality -6 < -2x

∴ x = 1 is the solution to the inequality -6 < -2x.

Conclusion:

x = 1 is a solution common to both inequalites.

7 0

3 years ago

Will mark brainliest :)

fiasKO [112]

Answer:

B im pretty sure

Step-by-step explanation:

7 0

2 years ago

Math problem I need help giving brainly! Super easy

Alborosie

Answer:

answer is -3

Step-by-step explanation:

one solution

6 0

2 years ago