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Sergeu [11.5K]
2 years ago
9

What is the solution for the system of equations? Use the substitution method to solve. Y=5−3x5x−4y=−3 Enter your answer by fill

ing in the boxes. ( , ​ ​).
Mathematics
1 answer:
Taya2010 [7]2 years ago
6 0

Using the substitution method to solve the linear system the value of x and y is 1 and 2 respectively.

<h3>What is the linear system?</h3>

It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width.

Given

The equations are shown below.

y = 5 - 3x .....1

5x - 4y = -3 .....2

Substitute equation 1 in equation 2. Then

\begin{aligned} 5x - 4(5-3x) &= -3\\\\5x - 20 + 12x &= -3\\\\17x &= -3 +20 \\\\17x  &= 17\\\\x &= 1\end{aligned}

Then substitute the value of x in equation 1.

y = 5- 3x\\\\y = 5-3*1\\\\y = 2

Thus, the value of x and y is 1 and 2 respectively.

More about the linear system link is given below.

brainly.com/question/20379472

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Answer:

The slope of line is 0 given points (2,8)(7,8)

Step-by-step explanation:

We need to find slope of line given points (2,8),(7,8)

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We are given:

x_1=2, y_1=8, x_2=7 \ and \ y_2=8

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Answer:

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440 = \pi *7*(7+\sqrt{h^2+7^2})\\\\440 = 7\pi (7 + \sqrt{h^2+7^2})\\\\\frac{440}{7\pi } = 7 + \sqrt{h^2+49}\\\\\frac{440}{7\pi } - 7 = \sqrt{h^2+49}\\\\\frac{440-49\pi}{7\pi} =\sqrt{h^2+49}\\\\

\frac{286.062}{21.99} =\sqrt{h^2+49}\\\\13.0087= \sqrt{h^2+49}\\\\(13.0087)^2 = (\sqrt{h^2+49})^2\\\\169.227 = h^2 +49\\\\169.227 - 49 =h^2\\\\120.227 = h^2\\\\h = \sqrt{120.227}  = 10.96in

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The correct answer would be chart A.

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