What is the solution for the system of equations? Use the substitution method to solve. Y=5−3x5x−4y=−3 Enter your answer by fill
1 answer:
Using the substitution method to solve the linear system the value of x and y is 1 and 2 respectively.
<h3>What is the linear system?</h3>It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width.
Given
The equations are shown below.
y = 5 - 3x .....1
5x - 4y = -3 .....2
Substitute equation 1 in equation 2. Then
Then substitute the value of x in equation 1.
Thus, the value of x and y is 1 and 2 respectively.
More about the linear system link is given below.
You might be interested in
The given equations are
(1)
(2)
When t=0, obtain
Obtain derivatives of (1) and find x'(0).
x' (t+1) + x - 4√x - 4t*[(1/2)*1/√x = 0
x' (t+1) + x - 4√x -27/√x = 0
When t=0, obtain
x'(0) + x(0) - 4√x(0) = 0
x'(0) + 9 - 4*3 = 0
x'(0) = 3
Here, x' means
.
Obtain the derivative of (2) and find y'(0).
2y' + 4*(3/2)*(√y)*(y') = 3t² + 1
When t=0, obtain
2y'(0) +6√y(0) * y'(0) = 1
2y'(0) = 1
y'(0) = 1/2.
Here, y' means
.
Because
, obtain
Answer:
The slope of the curve at t=0 is 1/6.
When t=0, obtain
Obtain derivatives of (1) and find x'(0).
x' (t+1) + x - 4√x - 4t*[(1/2)*1/√x = 0
x' (t+1) + x - 4√x -27/√x = 0
When t=0, obtain
x'(0) + x(0) - 4√x(0) = 0
x'(0) + 9 - 4*3 = 0
x'(0) = 3
Here, x' means
Obtain the derivative of (2) and find y'(0).
2y' + 4*(3/2)*(√y)*(y') = 3t² + 1
When t=0, obtain
2y'(0) +6√y(0) * y'(0) = 1
2y'(0) = 1
y'(0) = 1/2.
Here, y' means
Because
Answer:
The slope of the curve at t=0 is 1/6.