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2 years ago

Use the graph to find the

Mathematics

1 answer:

Dmitry [639]2 years ago

7 0

The y intercept is 2, because that is the value of y when it crosses the y axis.

Since the line is pointing down, it has a negative slope, and since the y value goes down 2 for every 3 x values, the slope is -2/3. You should always right the slope in rise/run form, or change in y/change in x.

Finally, write the equation in the form of y=mx+b, where m is the slope and b is the y intercept. This means the equation of the line is y=-2/3x+2.

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The slope of a line in a blueprint must be . A line is drawn that contains the points 5/6 < | m | <7/4. Determine if the l

padilas [110]

Sorry, a bit late but i took it and it was A.

4 0

2 years ago

Which inequality represents all possible solutions of −6n<−12?

muminat

Answer:

B n>2

Step-by-step explanation:

−6n<−12

Divide each side by -6, remembering to flip the inequality

-6n/-6 > -12/-6

n >2

5 0

3 years ago

Please help, Will mark brainliest

mihalych1998 [28]

Answer:

y = - 8 x + 2

Step-by-step explanation:

Use any two pairs to find the slope with

slope = (y2-y1)/(x2-x1)

for example: (0, 2), and (1, -6)

slope = (- 6 - 2) / (1 - 0) = - 8

so the equation should look like:

y = -8 x + b

use point (0, 2) to find b:

2 = - 8 (0) + b

b = 2

Then

y = - 8 x + 2

5 0

3 years ago

The table in the answer space shows some of the high-profile information, in cm, for 50 participants who have attended the schoo

harina [27]

mode is 8.Hope it helps

6 0

3 years ago

A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. a) E

polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) $\alpha =1-0.98=0.02$

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

$p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }$

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and $z_{\alpha/2}$ is the z-value that let a probability of $\alpha/2$ on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, $\alpha$ by 0.02 and $z_{\alpha/2}$ by 2.33

Where p' and $\alpha$ are calculated as:

$p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02$

So, replacing the values we get:

$0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438$

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence $1-\alpha$ is equal to 98%

It means the the level of significance $\alpha$ is:

$\alpha =1-0.98=0.02$

4 0

3 years ago