The sum of opposite angles are equal, so two of the angles are 45°. The sum of all angles about the intersection of two lines is 360°. So the remaining two angles are found by:
α=(360-2*45)/2
α=135° thus all four angles are:
45°,135°,45°,135°
It is true since you’re multiplying the same number on both the sides
Answer:
Step-by-step explanation:
There are 2 very distinct and important things that we need to know before completing the problem. First is that we are given that the cos of an angle is 1/3 (adjacent/hypotenuse) and it is in the first quadrant. We also need to know that the identity for sin2θ = 2sinθcosθ.
We already know cos θ = 1/3, so we need now find the sin θ. The sin ratio is the side opposite the angle over the hypotenuse, and the side we are missing is the side opposite the angle (we do not need to know the angle; it's irrelevant). Set up a right triangle in the first quadrant and label the base with a 1 (because the base is the side adjacent to the angle), and the hypotenuse with a 3. Find the third side using Pythagorean's Theorem:
which simplifies to
and
so
so that's the missing side. Now we can easily determine that

Now we have everything we need to fill in the identity for sin2θ:
and multiply all of that together to get

$16 I don’t have time to explain sorry I’m helping as many ppl as I can