<h2>
Answer with explanation:</h2>
The given function : 
Using completing the squares, we have
[∵ 
]
(1)
Comparing (1) to the standard vertex form 
, the vertex of function is at (h,k)=(-1,-4)
For x-intercept, put f(x)=0 in (1), we get
Square root on both sides, we get
∴ x intercepts : x= (-3,0) and (1,0)
For y-intercept put x=0 in (1), we get
∴ y intercept : (0,-3)
Axis of symmetry : 
In , a=1 and b=2
Axis of symmetry=
Answer: It is not possible to find the vertex of the stated equation as it is in the form of f(x) = mx + b, a linear equation.
Step-by-step explanation:
Being in the form f(x) = mx + b, it is not possible to find a vertex due to the fact that there is none. This is because when an equation is written in the linear form it is representing a line not a parabola.
Given a parabola it is possible to find a vertex because in that case there is one.
The answer is negative one hundred 95 or -195
Answer:
x= 35
Step-by-step explanation:
supposing we are finding x, we know that the line in the middle is the dimeter. so we know its a semicircle with an arc of 180 degrees. 180-110=70 divide that by two to get x which is 35.
Answer:
The base is: ![3 \sqrt[3]{4}](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B4%7D)
Step-by-step explanation:
Given
![f(x) = \frac{1}{4}(\sqrt[3]{108})^x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B4%7D%28%5Csqrt%5B3%5D%7B108%7D%29%5Ex)
Required
The base
Expand 108
![f(x) = \frac{1}{4}(\sqrt[3]{3^3 * 4})^x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B4%7D%28%5Csqrt%5B3%5D%7B3%5E3%20%2A%204%7D%29%5Ex)
Rewrite the exponent as:
Expand
Rewrite as:
![f(x) = \frac{1}{4}(3 \sqrt[3]{4})^x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B4%7D%283%20%5Csqrt%5B3%5D%7B4%7D%29%5Ex)
An exponential function has the following form:
Where
By comparison:
![b =3 \sqrt[3]{4}](https://tex.z-dn.net/?f=b%20%3D3%20%5Csqrt%5B3%5D%7B4%7D)
So, the base is:
