To find the time that it will take for the ball to hit the ground we need to solve:
p(t) = (-4.9 m/s^2)*t^2 + (15m/s)*t + 1m = 0m.
<h3>
¿How to find the motion equation for the ball?</h3>
We should start by the easier part, which is acceleration.
The only force acting on the ball will be the gravitational force, this means that the acceleration of the ball is -9.8 m/s^2
a(t) = -9.8 m/s^2
To get the velocity, we integrate over time, and remember that the constant of integration is equal to the initial velocity, which we already know is equal to 15m/s.
v(t) = (-9.8 m/s^2)*t + 15m/s.
To get the position equation we integrate again, this time the constant of integration is the initial position, which is 1m.
p(t) = (1/2)(-9.8 m/s^2)*t^2 + (15m/s)*t + 1m
p(t) = (-4.9 m/s^2)*t^2 + (15m/s)*t + 1m
The ball will hit the ground when the position is equal to zero, so we need to solve:
p(t) = (-4.9 m/s^2)*t^2 + (15m/s)*t + 1m = 0m.
If you want to learn more about motion equations, you can read:
brainly.com/question/605631
