To have an overall positive or negative charge. (as opposed to neutral one)
Answer:
A) 0.1 a, 0.9 A
Explanation:
According to the given information, all the individuals in the founder population had free earlobes. Since the allele for the free earlobes (A) is dominant over the one for the attached earlobes (a), the genotype of each of the homozygous dominant founder individual would be "AA". Humans are diploid and one individual has two alleles for each gene in its genome. Total number of alleles for the earlobe in the founder population = 10 x 2 = 20.
Frequency of dominant allele, A in the founder population = total number of homozygous dominant individuals x 2 + the total number of heterozygous genotype / total alleles for the earlobe in the population. There were 8 homozygous dominant and 2 heterozygous dominant individuals in the population.
So, frequency of dominant allele = 8 x 2 + 2 / 20 = 16 + 2 / 20 = 18/20 = 0.9
Since p+q=1; frequency of recessive allele "a" = 1-p = 1-0.9 = 0.1
<span>The amount of genes we have is considered an estimation. They
used to believe it was around or above 100,000. Then when the human genome project (HGP)
was completed in 2003 their estimation brought it down to 20,000 to 25,000. You
can find their current work at “national human genome research institute” and
also a free public database. </span>
Bacterial genes are organized into operons, clusters of coregulated genes, that are regulated such that they are all turned on or off together.
