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sveta [45]
3 years ago
9

Please help! (1 question)

Mathematics
1 answer:
Hitman42 [59]3 years ago
4 0

Answer:

it's c

it might be wrong because i dont know the question

but as a guess i pick c

in every multiple choice questton there is always a 60% chance the answer is c

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I know that it falls to the left and rises to the right but how do I express that here?
Jlenok [28]

Answer:

c

Step-by-step explanation:

4 0
3 years ago
25^(x+2) = (1/5)^(4x)
dangina [55]
The first step for solving this equation is to write 25^{x+2} in exponential form with a base of 5.
5^{2x+4} = ( \frac{1}{5}) ^{4x}
Write ( \frac{1}{5}) ^{4x} in exponential form with a base of 5.
5^{2x+4} = 5^{-4x}
Since the bases on both sides of the equal are the same,, set the exponents equal.
2x + 4 = -4x
Move the constant to the right side of the equation and then change its sign.
2x = -4x - 4
Now move the variable to the left side and change its sign.
2x + 4x = -4
Collect the terms with an x variable.
6x = -4
Lastly,, divide both sides of the equation by 6 to get your final answer.
x = - \frac{2}{3}
Let me know if you have any further questions.
:)
8 0
3 years ago
A mapscale says: 2 inches equals 25 miles. How many miles does 6 inches represent??
mario62 [17]
The answer is 75 miles!
you can set up a proportion- 2/25=6/x and cross multiply, then solve for x in the equation 2x=150
4 0
3 years ago
A simple random sample from a population with a normal distribution of 103 body temperatures has x overbarequals98.90degrees Upp
Shtirlitz [24]

Answer:

98.90-1.984\frac{0.62}{\sqrt{103}}=96.98    

98.90+ 1.984\frac{0.62}{\sqrt{103}}=100.82    

The 95% confidence interval would be given by (96.98;100.82)    

Step-by-step explanation:

Information given

\bar X=98.90 represent the sample mean

\mu population mean (variable of interest)

s=0.62 represent the sample standard deviation

n=103 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=103-1=102

Since the Confidence is 0.95 or 95%, the significance is \alpha=0.05 and \alpha/2 =0.025, and the critical value for this case would be t_{\alpha/2}=1.984

And replacing we got:

98.90-1.984\frac{0.62}{\sqrt{103}}=96.98    

98.90+ 1.984\frac{0.62}{\sqrt{103}}=100.82    

The 95% confidence interval would be given by (96.98;100.82)    

8 0
3 years ago
Malik solved this system of equations.
larisa [96]

We can solve for x in by substituting 'y=15-5x' from the second one into the first equation, because in the second equation, y has no coefficient, which will make it easier to substitute.

4 0
3 years ago
Read 2 more answers
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