10 4/5 = 54/5
54/5 x 4 = 216 / 5= 43 1/5
unit rate = 43 1/5 ounces / per cake
Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Answer:
16 - 5 
Step-by-step explanation:
Answer: The answer is 60
Step-by-step explanation: 40% = .4 because % means hundredths. So 40% = 40/100 = .4
Let x be the total number of marbles.
Then, .4x = 24
Divide both sides by .4
x = 60 and 24 is 40% of 60 marbles
Answer:
The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for the difference between population means is:
The information provided is as follows:
The critical value of <em>z</em> for 98% confidence level is,
Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:
Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).
