Oh boy, here we go again
First we must convert 1 2/3 to an improper fraction. By doing this, we get 5/3 (3/3 + 2/3)
So now we have 273 / 5/3
To divide this easier we can do something that when I learned it was called (keep, change, flip) which basically means keep the first fraction, change the sign from division to multiplication, and flip the second fraction
This now turns into: 273/1 * 3/5
Combine 273 and 3/5
273⋅3/5
Multiply 273
by 3
819/5
is your answer
Answer:
25 meals
Step-by-step explanation:
She has 10 pounds total and she feeds 2/5 per meal, so we do 10/(2/5)) to get 25
Hope this helps
The answer is false, it is only true for postulates, not conjectures.
A, 57%, because 0.40 divided by all possible outcomes, which is 0.70 because we know it will not be sunny tomorrow, is 0.57.
Answer:
Tn = 2Tn-1 - Tn-2
Step-by-step explanation:
Before we can generate the recursive sequence, we need to find the nth term of the given sequence.
nth term of an AP is given as:
Tn = a+(n-1)d
If a17 = -40
T17 = a+(17-1)d = -40
a+16d = -40 ...(1)
If a28 = -73
T28 = a+(28-1)d = -73
a+27d = -73 ...(2)
Solving both equations simultaneously using elimination method.
Subtracting 1 from 2 we have:
27d - 16d = -73-(-40)
11d = -73+40
11d = -33
d = -3
Substituting d = -3 into 1
a+16(-3) = -40
a - 48 = -40
a = -40+48
a = 8
Given a = 8, d = -3, the nth term of the sequence will be
Tn = 8+(n-1) (-3)
Tn = 8+(-3n+3)
Tn = 8-3n+3
Tn = 11-3n
Given Tn = 11-3n and d = -3
Tn-1 = Tn - d... (3)
Tn-1 = 11-3n +3
Tn-1 = 14-3n
Tn-2 = Tn-2d...(4)
Tn-2 = 11-3n-2(-3)
Tn-2 = 11-3n+6
Tn-2 = 17-3n
From 3, d = Tn - Tn-1
From 4, d = (Tn - Tn-2)/2
Equating both common difference
(Tn - Tn-2)/2 = Tn - Tn-1
Tn - Tn-2 = 2(Tn - Tn-1)
Tn - Tn-2 = 2Tn-2Tn-1
2Tn-Tn = 2Tn-1 - Tn-2
Tn = 2Tn-1 - Tn-2
The recursive formula will be
Tn = 2Tn-1 - Tn-2
