The equation computed shows that the numbers will be 9, 11 and 13.
<h3>How to illustrate the information?</h3>
Let the numbers be:
First number = x
Second number = x + 2,
Third number = x + 4.
Total of the numbers = 33
The equation will be:
= first + second + third number
x + x + 2 + x + 4 = 33
3x + 6 = 33
Collect like terms
3x = 33 - 6
3x = 27.
Divide both side by 3
3x/3 = 27/3
x = 9
First number = x = 9
Second number = x + 2 = 9 + 2 = 11
Third number = x + 4. = 9 + 4 = 13
The numbers will be 9, 11, and 13.
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Illustrate the equation to find three consecutive odd integers whose sum is 33.
Answer:
$10.71
Step-by-step explanation:
y × 35 = 3.75 × 100
35y = 375
35y ÷ 35 = 375 ÷ 35
y = 10.7142857143
10.7142857143 round to 10.71
Answer:
no solutions.
Step-by-step explanation:
8x + 14 -4x = 9+4x -5
8x-4x -4x = 9-5-14
0x = -10
anything multiplied by 0 is 0, so it's impossible to get -10 by multiplying by 0
Answer:
Step-by-step explanation:
I think you meant y = -2x + 5.
x y = -2x + 5
0 5
1 -2(1) + 5 = 3
2 -2(2) + 5 = 1
Note that every time you increase x by 1, y decreases by 2.
Step-by-step explanation:
F(x) = ∫ₐˣ t⁷ dt
F(x) is the area under f(t) between t=a and t=x. When x=a, the width of the interval is 0, so the area is zero.
F(6) = 0, so a = 6.
F(x) = ∫₆ˣ t⁷ dt
F(6) = ∫₆⁶ t⁷ dt
F(6) = 0
