Answer:
s = 4
Step-by-step explanation:
The equation for the line of best fit for the data is p=25s+40.
Where p is no. of points and s is no. fo strikes
We need to find the number of strikes made by a bowler with 140 points.
Put p = 140
p=25s+40
140 = 25s+40
Subtract 40 to both sides,
140-40 = 25s+40-40
100 = 25s
⇒ s = 4
So, there are 4 strikes made by a bowler with 140 points.
Answer:
Step-by-step explanation:
It said the greatest amount,
So change 50% to .50
120x.50=60
First, let's expand the right side. Now our equation is

Now, we gather all the terms with x in it on the left side, and the numbers without x on the right. We get:

And then we can make this

We divide both sides by 12 to get x on its own, so x = 13/12 or 1.08
A right angles is 90 degrees, which means that 90-55= x
x = 35 degrees
<span><span>13−<span>6x</span></span>=<span><span><span>(<span><span>2x</span>−5</span>)</span>2</span>+3</span></span>Step 1: Simplify both sides of the equation.<span><span><span>−<span>6x</span></span>+13</span>=<span><span><span>4<span>x2</span></span>−<span>20x</span></span>+28</span></span>Step 2: Subtract 4x^2-20x+28 from both sides.<span><span><span><span>−<span>6x</span></span>+13</span>−<span>(<span><span><span>4<span>x2</span></span>−<span>20x</span></span>+28</span>)</span></span>=<span><span><span><span>4<span>x2</span></span>−<span>20x</span></span>+28</span>−<span>(<span><span><span>4<span>x2</span></span>−<span>20x</span></span>+28</span>)</span></span></span><span><span><span><span>−<span>4<span>x2</span></span></span>+<span>14x</span></span>−15</span>=0</span>Step 3: Use quadratic formula with a=-4, b=14, c=-15.<span>x=<span><span><span>−b</span>±<span>√<span><span>b2</span>−<span><span>4a</span>c</span></span></span></span><span>2a</span></span></span><span>x=<span><span><span>−<span>(14)</span></span>±<span>√<span><span><span>(14)</span>2</span>−<span><span>4<span>(<span>−4</span>)</span></span><span>(<span>−15</span>)</span></span></span></span></span><span>2<span>(<span>−4</span>)</span></span></span></span><span>x=<span><span><span>−14</span>±<span>√<span>−44</span></span></span><span>−<span>8</span></span></span></span>