Answer:
Step-by-step explanation:
Given
--- driver 1
-- driver 2
Required
The time they passed each other
First, we determine the function of driver 2.
We have that:
and
So, the function is:
The time they drive pass each other is calculated as:
Collect like terms
Divide through by 2t
Solve for -8t
Solve for t
We know that
[volume of a cube]=b³---------> b=∛Volume
b------> is the side length of a cube
The top block was 64 cm³------> b1=∛64-------> b1=4 cm
The middle block was 125 cm³------> b2=∛125------> b2=<span>5 cm
T</span>he biggest block was 729 cm³------> b3=√729------> b3=<span>9 cm
[</span><span>the stack of blocks tall]=b1+b2+b3-------> 4+5+9-----> 18 cm
</span><span>
the answer is
</span>the stack of blocks was 18 cm tall<span>
</span>
You would first make the fractions improper (making the numerator bigger then the denominator) in order to do that times the denominator with the whole number and add the numerator.
Ex) 3*8 = 24 + 5 = 29/8
Then you would add both of the improper fractions
In finding this value you average lower and upper bound
(0.6+0.82)/2 = 0.71
=0.71 estimated
margin of error = distance from estimate point lower/ upper bound
This interval will be twice margin error
(0.82-0.6)/2 = 0.11
How far is 0.82 from 0.71 ??
=0.11=11%
