Answer:
<u><em>Sammie</em></u>
Step-by-step explanation:
<u><em>Jane</em></u>
First, convert R as a percent to r as a decimal
r = R/100
r = 5/100
r = 0.05 rate per year,
Then solve the equation for A
A = P(1 + r/n)nt
A = 550.00(1 + 0.05/4)(4)(10)
A = 550.00(1 + 0.0125)(40)
A = $903.99
<u><em>Sammie</em></u>
First, convert R as a percent to r as a decimal
r = R/100
r = 7/100
r = 0.07 rate per year,
Then solve the equation for A
A = P(1 + r/n)nt
A = 550.00(1 + 0.07/12)(12)(10)
A = 550.00(1 + 0.005833333)(120)
A = $1,105.31
<u><em>
</em></u>
Answer:
The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

93% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).
Answer:
Step-by-step explanation:
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