First set up a linear equation and using the x and y values in the table see if it solves.
It doesn't solve so we know it isn't linear. ( I won't show all those steps because they aren't needed.)
Using the quadratic formula y = ax^2 +bx +c
Build a set of 3 equations from the table:
C is the Y intercept ( when X is 0), this is shown in the table as 6
Now we have y = ax^2 + bx + 6
-2.4 =4a-2b +6
1.4 = a-b +6
Rewrite the equations
a=b/2 -2.1
1.4 = b/2-2.1 +6
b = 5
a = 5/2 -2.1 = 0.4
replace the letters to get y = 0.4x^2 + 5x +6
PEMDAS
P- none
E- none
M- none
D- (3/1/3=1)
AS- 9-1+1=9
The answer is A.
The function f(x) is defined in to different ways depending on the value of X. When x is < 5, use the expression 2x - 1 to evaluate the function When x is ≥ 5, use the expression x2 - 3 for example f(1) = 2(1) - 1 = 1 f(10) = (10)2 - 3 = 97
Answer:
a. y = -x² + 2x - 8
b. y = 
c. y = x³+ 3
Step-by-step explanation:
Answer:
Concept: Mathematical Derivation
- We are given x^2 +6x+2x+12
- Hence we simplify: x^2 + 8x +12
- Now we factor: (x+2)(x+6)
- By mathematical logic we now proved that the roots are x=-2 and x=-6
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