The more reasonable measurement of the distance between the tracks on a CD is 1.6 ⋅ 10^-3 mm. This is also equal to 0.0016mm. <span>1.6 ⋅ 10^3 mm is too large for a CD track</span>
Answer:
C
Step-by-step explanation:
We can first move the variables to one side.
We can do this by subtracting 6x from both sides.
12x^2-6x=0
Now, we can factor out 6x.
6x(2x-1)=0
Since it equals 0, we know that 2x-1=0, or 6x=0.
This is because when ab=0, either a or b must equal 0.
So we can set both of these equal to 0 to solve.
6x=0
Divide both sides by 6.
x=0
2x-1=0
Add 1 to both sides.
2x=1
Divide both sides by 2.
x=1/2
The numbers are 6 and -2.
6 + -2 is 4
as well as 6 x -2 is -12
