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Charra [1.4K]
3 years ago
5

What stress will shift the following equilibrium system to the left? 2SO2(g) + O2(g) ⇌ 2SO3(g); ΔH= –98.8 kJ/mol

Chemistry
1 answer:
svlad2 [7]3 years ago
6 0

Answer:

The stress that will shift the equilibrium system to the right is decreasing the temperature

Explanation:

Chemical equilibrium

This is a state where there is no observable changes in the properties of the system with time.

From the above, a French scientist establishes a principle which states that when an external constraints such as change in temperature, pressure and concentration is imposed on a system in equilibrium, the equilibrium will shift to neutralise the effect.

Furthermore, the principle explained that:

An increase in temperature of an exothermic reaction (i.e ΔH= –ve) will shift the equilibrium backward.

A decrease in temperature of an exothermic reaction (i.e ΔH= –ve) will shift the equilibrium forward.

An increase in temperature of an endothermic reaction (i.e ΔH= +ve) will shift the equilibrium forward.

A decrease in temperature of an exothermic reaction (i.e ΔH= +ve) will shift the equilibrium back.

How to determine which stress that will shift the equilibrium forward (right)

2SO₂(g) + O₂(g) ⇌ 2SO₃(g); ΔH= –98.8 KJ/mol

From the equation above, we can see that the reaction is exothermic reaction (i.e ΔH= –ve).

Therefore, decreasing the temperature will shift the equilibrium to the right.

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Si tomas 100ml de una solución de Nacl 4m y se disuelve en 200ml utilizando el mismo solvente ¿cuál será la nueva concentración?
g100num [7]

Respuesta:

2 m

Explicación:

Paso 1: Información provista

  • Volumen inicial (V₁): 100 mL
  • Concentración inicial (C₁): 4 m
  • Volumen final (V₂): 200 mL
  • Concentración final (C₂): ?

Paso 2: Calcular la concentración de la solución final

Queremos perparar una concentración diluida a partir de una concentrada. Podemos calcular la concentración de la solución diluida usando la regla de dilución.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 4 m × 100 mL / 200 mL = 2 m

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3 years ago
What is the ph of a solution with hydrogen ion concentration of 0.001m?
lys-0071 [83]
Find the pH using the concentration of hydrogen ions [H+] of 0.001M (molarity) by taking the negative log of the value:

-log[H+]=pH
-log[0.001] = pH
-log[1x10^-3]=pH
3=pH
6 0
3 years ago
Name:_____________________________________________________ Date:___________ Period:_________ 3/23 - 3/27 Assignment 1: Gas Law P
crimeas [40]

Answer:

The answers are;

1. 8.2 liters

2. 1214.84 ml

3. 318.027 K

4. 4.00 l.

Explanation:

1. Boyle's law states that the volume of  given mass of gas is inversely proportional to its pressure at constant temperature

that is

P₁·V₁ = P₂·V₂

Where:

P₁ = Initial pressure = 40.0 mm Hg

V₁ = Initial volume = 12.3 liters

P₂ = Final pressure = 60.0 mm Hg

V₂ = Final volume = Required

From P₁·V₁ = P₂·V₂, V₂ is given by

V_2=\frac{P_1\cdot V_1}{P_2} = \frac{40.0 mm Hg\cdot 12.3 l}{60.0 mm Hg} =  8.2 l

The volume reduces to V₂ = 8.2 liters

2. Here Charles law states that

\frac{T_1}{V_1} =\frac{T_2}{V_2}

T₁ = Initial temperature = 27.0 °C = 300.15 K

V₁ = Initial volume = 900.0 mL

T₂ = Final temperature = 132.0 °C = 405.15 K

V₂ = Final volume = Required

Therefore  V_2 =\frac{T_2\cdot V_1}{T_1} = \frac{405.15 K\times 900.0 mL}{300.15 K} = 1214.84 ml

V₂ = 1214.84 ml

3.  Gay-Lussac's Law states that

\frac{T_1}{P_1} =\frac{T_2}{P_2}

Where:

P₁ = Initial pressure = 15.0 atmospheres

T₁ = Initial temperature = 25.0 °C = 298.15 K

P₂ = Final pressure = 16.0 atmospheres

T₂ = Final temperature = Required

∴ T_2 = \frac{T_1\times P_2}{P_1}

=  \frac{298.15 K\times 16.0atm}{15.0atm} = 318.027 K

T₂ = 318.027 K

4. Avogadro's law states that,

Equal volume of all gases at the same temperature and pressure contain equal number of molecules.

Therefore if 5.00 moles of gas occupies 2.00 l volume, then

1 moles will occupy 2.00/5 l volume and

10 moles will occupy 2.00/5 × 10 or 4.00 l volume.

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