Answer:
The Amount in account after 6 years is $4014.976
Step-by-step explanation:
Given as :
The principal = p = $3500
The rate of interest = r = 2.29% compounded monthly
The time period = t = 6 years
Let The Amount in account after 6 years = $A
<u>From Compound Interest method</u>
Amount = Principal × 
Or, A = p × 
Or, A = $3500 × 
Or, A = $3500 × 
Or, A = $3500 × 1.147136
∴ A = $4014.976
So,The Amount in account after 6 years = A = $4014.976
Hence, The Amount in account after 6 years is $4014.976 Answer
Answer:
2(W + 6) + 2W = 90 where W = the width.
Step-by-step explanation:
The perimeter is 2L + 2W where L = the length and W = the width of the rectangle.
The length L = W + 6 so the equation is:
2(W + 6) + 2W = 90.
Answer:
It is congruent doe to the angle side angle congruence thereom AKA ASA
Step-by-step explanation:
That means there are two angles and one side in between. A pair of triangles that follow this rule has an angle that is congruent to one angle. Then a side that has a tick mark after the angle must match another. Then the last angle has to match another angle ( and it can't be the same angle as before). Usually the first pair angles have 1 semicircle and the second pair has 2 semicircles.
We need to find the points that are solutions, that is, the points that lie in the shaded region.
Let's try the ordered pair (1,2). This isn't in the shaded region, so it is not a solution of the system.
The same goes for (-10, 10) and (-2,0).
But when you plot (0,10), it does lie in the shaded region, so it's a solution of the system of inequalities.