LM is the diameter of OP. N L *not drawn to scale IfmXLMN = 48° what is mZNLM? A. 24° B. 42° C. 48° D. 66° E. 84

Mathematics

1 answer:

Sindrei [870]3 years ago

3 0

Answer:

Step-by-step explanation:

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-7,-12,-17,-22,-27 find the nth term

Bess [88]

Answer:

-2 - 5n

Step-by-step explanation:

-7, -12, -17, -22, -27.....

Arithmetic Sequence

first term a = -7

difference = d = -12 - (-7) = -12 + 7 = (-5)

nth term = a + (n-1)d

= -7 + (n-1)*(-5)

= -7 + (-5)*n -1 * (-5)

= -7 - 5n + 5

= -2 - 5n

6 0

3 years ago

Mackenzie earns 49 00 in a day I a normal

oee [108]

Answer:

245

Step-by-step explanation:

$49.00 times 5 is 245. The 5 came from the question because it says a normal work week has 5 days so you would multiply $49.00 by 5

5 0

2 years ago

A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.

tatyana61 [14]

Answer:

(a) $g(n)=0.05\cdot 2^n$

(b) $g^{-1}(n)=\log_{2}20g(n)$

Step-by-step explanation:

Part A

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

$g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n$

Part B

$g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)$

Part C

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

$g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43$