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Agata [3.3K]
3 years ago
15

I am really confused and need help.

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0

Answer:

The 3rd, 4th, and 6th are correct but I'm not sure if the second would be correct as well.

Step-by-step explanation:

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In March, there will be two conferences: one for math and one for history. So far, 7 people have signed up for the math conferen
otez555 [7]

Answer:

After 4 days, the number of people attending both conferences be the same.      

Step-by-step explanation:

We are given the following in the question:

Maths conference:

Number of people already signed = 7

Number of people who sign up each day = 2

Thus, the number of people who will sign up for maths conference in x days will be given by the linear function:

 f(x) = 7+2x

History conference:

Number of people already signed =11

Number of people who sign up each day = 1

Thus, the number of people who will sign up for maths conference in x days will be given by the linear function:

 g(x) =11+x

Both conference will have same number of people when

f(x) = g(x)\\\Rightarrow 7 + 2x = 11+x\\\Rightarrow x = 4

Thus, after 4 days, the number of people attending both conferences be the same.

5 0
3 years ago
In 2012, the population of a city was 6.29 million. The exponential growth rate was
RoseWind [281]

9514 1404 393

Answer:

  a) P(t) = 6.29e^(0.0241t)

  b) P(6) ≈ 7.3 million

  c) 10 years

  d) 28.8 years

Step-by-step explanation:

a) You have written the equation.

  P(t) = 6.29·e^(0.0241·t)

__

b) 2018 is 6 years after 2012.

  P(6) = 6.29·e^(0.0241·6) ≈ 7.2686 ≈ 7.3 . . . million

__

c) We want t for ...

  8 = 6.29·e^(0.0241t)

  ln(8/6.29) = 0.0241t

  t = ln(8/6.29)/0.0241 ≈ 9.978 ≈ 10.0 . . . years

__

d) Along the same lines as the calculation in part (c), doubling time is ...

  t = ln(2)/0.0241 ≈ 28.7613 ≈ 28.8 . . . years

4 0
3 years ago
Use 2 as a factor to write an expression that is equivalent to the ​expression 8x+6y . ​
posledela
2(4x + 3y). You just factor out the two
6 0
3 years ago
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