1 Face has 0 face painted
Step-by-step explanation:
As per the question a painted cube that is cut into 27 equal-size smaller cubes has been cut into a 3 * 3 * 3 arrangement.
There is 1 cube in the very center
On each of the 6 sides of the cube, there is a central smaller cube that is painted once.
Of the 27 (3*3*3) smaller cubes formed by the cutting, 1 gets no paint, 6 are painted on 1 face, 12 are painted on 2 faces, and 8 are painted on 3 faces (total 27 cubes).
1 (no paint) + 6 (painted 1) + 12 (painted 2) + 8 (painted 3) = 27 total
The sum of the painted faces (of the small cubes) is 54 (which is 6*9).
Answer:
did that first one its false
A= 53, B= 100, C= 27 (the last option)
BC is the longest side because it is opposite the largest angle ( not true)
Answer:
modify tge production
Step-by-step explanation:
Answer:
It is equal to each other
Step-by-step explanation:
![\sqrt{\frac{1}{x^2}} = \frac{1}{x}\\\sqrt[3]{\frac{1}{x^3}} = \frac{1}{x}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B1%7D%7Bx%5E2%7D%7D%20%3D%20%5Cfrac%7B1%7D%7Bx%7D%5C%5C%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7Bx%5E3%7D%7D%20%3D%20%5Cfrac%7B1%7D%7Bx%7D)
Answer:
AD is Congruent to BC and it's given, (given just means that it was already said or stated, and you don't need to do the work to find it) Angle DAC would be congruent to angle BAC (if that doesn't work, rearrange them to look like angle CAB). AC would be congruent to DB. Triangle ADC would be congruent to triangle BCD by (since i don't know exactly which way the letters are arranged is would either be SAS or SSA) and that's because you know two of the sides are congruent to each other and one angle.
I tried hard to sketch out what the shape looked like based on the information given, and that's because I need a visual of what the shape looks like. Sorry, this took so long to answer.
