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borishaifa [10]
3 years ago
11

I’m on my last question and i’m stuck, someone help me please

Mathematics
2 answers:
Charra [1.4K]3 years ago
4 0

Answer:

(2, 2) and (3, 4)

Step-by-step explanation:

as x increases by 1, y increases by 2. so, just add 2 to the last y value to get the answer.

baherus [9]3 years ago
3 0

Answer:

2         4

Step-by-step explanation:

plug in the x value give into the equation to get the y vaule so 2(2)-2=4-2=2

then 2(3)-3=6-2=4

Hope this helps! :)

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At 4:00p.m the temperature was 90F after this point the temperature dropped 1.5F per hour until sunrise the next morning write a
irina [24]

Answer:

90t-21t=69t

Step-by-step explanation:

4:00pm to 6:00 am is 14 hours. 14 x 1.5 is in fact 21 which means the temperature dropped 21 degrees in those 14 hours.

3 0
4 years ago
(2+x)dy/dx=3y need help
den301095 [7]
(2+x) \frac{dy}{dx} =3y
\frac{1}{3y} dy= \frac{1}{2+x} dx
\int { \frac{1}{3y} } \, dy = \int { \frac{1}{2+x} } \, dx
\frac{1}{3}\ln(3y) = \ln(2+x) + C
(raise both to the power e): e^{ \frac{1}{3}\ln(3y)}=e^{\ln(k(2+x))}
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y= k(2+x)^3
5 0
3 years ago
Please help! posted picture of question
Dvinal [7]
Since the graph of the given functions is a straight line, the graph belongs to a linear function, as all linear functions have their graphs as a straight line. For a non-linear function the graph is not a straight line. 

For a relation (non-function), the line passes through same value of x for more than one points. 

Hence the correct answer is "Linear Function"
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3 years ago
A 650-pund snowmobile trailer is sitting on an exit ramp inclined at 40 degrees
Dima020 [189]
Um what. This doesn’t make sense. Your not even asking a question
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3 years ago
1.Encuentra la ecuación de la circunferencia que tiene como ecuación ordinaria (x-4)² + (y+5)²= 25 2- encuentra la ecuación gene
rodikova [14]

Responder:

1) x² + y²-8x + 10y + 16 = 0

2) x² + y² + x + 18y + 33 = 0

Explicación paso a paso:

A partir de la pregunta, debemos expresar la ecuación en la forma estándar de un círculo expresado como;

x² + y² + 2gx + 2fy + c = 0 donde;

(-g, -f) es el centro.

1) Para la ecuación (x-4) ² + (y + 5) ² = 25

Expande el paréntesis;

(x-4) ² + (y + 5) ² = 25

x²-8x + 16 + y² + 10x + 25 = 25

x²-8x + 16 + y² + 10y + 25-25 = 0

Recopile términos similares;

x² + y²-8x + 10y + 16 + 0 = 0

<em>x² + y²-8x + 10y + 16 = 0 </em>

<em>Por lo tanto, la ecuación requerida es x² + y²-8x + 10y + 16 = 0 </em>

<em> </em>

2) Para la expresión (x + 1) ² + (y + 9) ² = 49

x² + x + 1 + y² + 18y + 81 = 49

x² + x + 1 + y² + 18y + 81-49 = 0

Recopile términos similares;

x² + y² + x + 18y + 82-49 = 0

<em>x² + y² + x + 18y + 33 = 0 </em>

<em>Por tanto, la ecuación requerida es x² + y² + x + 18y + 33 = 0</em>

4 0
3 years ago
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