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Veronika [31]
3 years ago
12

Which show a set of prime factors A. 2, 17 B. 2, 4, 5 C. 4, 11 D. 2, 25

Mathematics
2 answers:
Kipish [7]3 years ago
7 0

Answer:

i think it D if no im so sorry :)

Step-by-step explanation:

Alex787 [66]3 years ago
6 0

Answer: A.2,17

Step-by-step explanation:

Prime numbers are those which are divisble by 1 and itself  so 2,17 are

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There will be 810 tickets in all.
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3 years ago
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Hey !! Can someone please help me with this??
Katyanochek1 [597]

Answer:

8^2 and 4 x 4 x 4

Step-by-step explanation:

4 to the third power, is the same as 4 x 4 x 4.

This is then equal to 64.

8 squared is also equal to 64, making it also an answer.

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3 years ago
Make r the subject of t = 6r^2 + 6
SpyIntel [72]

First step, divide 6 from both sides.

t/6=r^2+1

second step, subtract 1 from both sides

t/6 -1=r^2

Now take the square root of each side.

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Done!

3 0
3 years ago
Write the explicit formula for the geometric sequence.<br><br> a1 = -5 a2 = 20 a3 = -80
Anni [7]
a_1 = -5;\ a_2 = 20;\ a_3 = -80 \\\\a_2:a_1=r\ and\ a_3:a_2=r\\\\r=20:(-5)=-4\ check\ r=-80:20=-4\\\\a_n=a_1r^{n-1}\to a_n=-5\cdot(-4)^{n-1}=-5\cdot(-4)^{-1}\cdot(-4)^n\\\\=-5\cdot\left(-\dfrac{1}{4}\right)\cdot(-4)^n=\dfrac{5}{4}\cdot(-4)^n\\\\Answer:\boxed{a_n=-5\cdot(-4)^{n-1}\ other\ a_n=\frac{5}{4}\cdot(-4)^n}
6 0
3 years ago
Solve the “and” compound inequality for –1 &lt; 6x + 1 ≤ 13
ser-zykov [4K]

Answer:

-1/3 < x <(or equal to) 2

Step-by-step explanation:

Firstly divide your inequality into two separate inequalities...

1) -1 < 6x + 1...then solve for the first one..,which then gives you....;

-2 < 6x....which gives us our first solution (x > -1/3)

Then the second inequality

2) 6x + 1 <(or equal to) 13

which then gives you....,

6x <(or equal to) 12...which then gives our second solution...( x <(or equal to) 2)

Then combine the two solutions into a compound solution

-1/3 < x <(or equal to) 2

8 0
3 years ago
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