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Lilit [14]
2 years ago
5

Write an expression using multiplication and addition with a sum of 16. (PLZ HELP!!!!)

Mathematics
1 answer:
Svetach [21]2 years ago
7 0
Write an expression using multiplication and addition with a sum of 16:

2 x 6 +4
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The equation V = 16300 (0.94)^t represents the value (in dollars) of a car t years after its purchase. Use this equation to comp
Dafna1 [17]

Solution:

Given:

V=16300(0.94)^t

The value of a car after t - years will depreciate.

Hence, the equation given represents the value after depreciation over t-years.

To get the rate, we compare the equation with the depreciation formula.

\begin{gathered} A=P(1-r)^t \\ \text{where;} \\ P\text{ is the original value} \\ r\text{ is the rate} \\ t\text{ is the time } \end{gathered}

Hence,

\begin{gathered} V=16300(0.94)^t \\ A=P(1-r)^t \\  \\ \text{Comparing both equations,} \\ P=16300 \\ 1-r=0.94 \\ 1-0.94=r \\ r=0.06 \\ To\text{ percentage,} \\ r=0.06\times100=6\text{ \%} \\  \\ \text{Hence, } \\ P\text{ is the purchase price} \\ r\text{ is the rate} \end{gathered}

Therefore, the value of this car is decreasing at a rate of 6%. The purchase price of the car was $16,300.

5 0
8 months ago
A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int
Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}

By expanding the previous equation:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0

Since there is no accumulation within the tank, expression is simplified to this:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}, where c(0) = 0 \frac{pounds}{gallon}.

\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}

The solution of this equation is:

c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})

The salt concentration after 8 minutes is:

c(8) = 0.166 \frac{pounds}{gallon}

The instantaneous amount of salt in the tank is:

m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds

3 0
3 years ago
Figure B is a scaled copy of Figure A.
elixir [45]

Answer:

The scale factor would be 1/2.

Step-by-step explanation:

2 of the sides both are 4 units.

If you go to figure B, it got smaller.

So in this case, you would divide.

On figure B, 2 of the sides are 2 units.

If you did it in reverse, you would get 2 because 2 times 2 is 4.

But we divide, so 4/2 is 2, so the scale factor would be:

1/2

Hope this helped!

And brainliest pls :)

6 0
1 year ago
What is the prime factorization of 140? A 2^2×3×7 B. 2^3×7 C. 4×5×7 D. 2^2×5×7​
Andreyy89

Answer:

Step-by-step explanation:

7 0
2 years ago
You move down 6 units. You end at (10, 4). Where did you start?
Alexandra [31]

Answer:

(10,10)

Step-by-step explanation:

coordinates are (x,y)

x is horizontal(left and right), y is vertical (up and down)

going down 6 means subtracting 6 from the second number

lets reverse that to go up and add 6 back

4+6=10

so the original point was (10,10)

8 0
2 years ago
Read 2 more answers
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