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Lilit [14]
3 years ago
5

Write an expression using multiplication and addition with a sum of 16. (PLZ HELP!!!!)

Mathematics
1 answer:
Svetach [21]3 years ago
7 0
Write an expression using multiplication and addition with a sum of 16:

2 x 6 +4
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A sport analyst wants to determine the mean salary of a Baseball player for 2015. He believes an estimate of this average salary
djyliett [7]

Answer:

<em>The large sample size 'n' =  199.6569≅ 200</em>

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given Standard deviation of salary for all baseball players for 2015 is about $5,478,384.55

<em>Standard deviation of  of salary for all baseball players for 2015 </em>

<em>   (S.D ) σ =  $5,478,384.55</em>

Given estimate of this average salary for all baseball players for 2015

                          =  $497,000

<em>Given Margin of error of error is  =  $497,000 </em>

<em>Level of significance ∝ = 80% </em>

<em>The critical value Z₀.₂₀ = 1.282  </em>

<u><em>Step(ii):</em></u><em>-</em>

<em>Margin of error of error is  determined by</em>

<em>           </em>M.E = \frac{Z_{0.20} S.D}{\sqrt{n} }<em></em>

<em>          </em>497,000 = \frac{1.282 X 5,478,384.55}{\sqrt{n} }<em></em>

Cross multiplication , we get

 \sqrt{n}  = \frac{1.282 X 5,478,384.55}{497,000 }

On calculation , we get

√n = 14.13

<em>Squaring on both sides, we get</em>

n = 199.6569

<u><em>Conclusion</em></u><em>:-</em>

<em>The large sample size 'n' =  199.6569≅ 200</em>

<em>    </em>

<em></em>

7 0
3 years ago
The basic unit in which data are stored in an accounting system is called an __________. These storage units should be so constr
mash [69]

Answer:

an accounts; credit or debit.

Step-by-step explanation:

Remember, accounting involves activities done to keep financial records. Interestingly, a similar term is used to refer to the basic unit in which data are stored in an accounting system called accounts.

Also, we need to bear in mind that this financial records written as storage units would include incoming or outgoing money measurements often called debit or credit transactions in the items for which they are established.

6 0
3 years ago
what do u have to do????????????????????????????????????????????????????????????????????????????????????????????????????????????
Setler79 [48]

Step-by-step explanation:

<u>Step 1:  Answer the question</u>

They are independent because the cards are always going to stay the same.  If each card that was picked and discarded, that would alter the future which would make it dependent.  But... since it doesn't change the cards, it is independent.

Answer: independent

5 0
3 years ago
Read 2 more answers
Find a vector of magnitude 3 in the direction of v = 10i - 24k. The vector is Oi-Oj+k (Simplify your answer. Use integers or fra
Soloha48 [4]

Given :

A vector v = 10i - 24k.

To Find :

A vector of magnitude 3 in the direction of v = 10i - 24k.

Solution :

Unit vector in the direction  of vector v is :

\^{v}=\dfrac{v}{|v|}\\\\\^{v}=\dfrac{10i-24k}{\sqrt{10^2+24^2}}\\\\\^{v}=\dfrac{10i-24k}{26}

Now , vector of magnitude 3 in direction v is :

r=3 \^{v}\\\\r=3\times \dfrac{ (10i-24k)}{26}\\\\r=\dfrac{3}{13} (5i-12k)

Hence , this is the required solution .

6 0
3 years ago
A person purchased a slot machine and tested it by playing it 1,137 times. There are 10 different categories of outcomes, includ
ivann1987 [24]

Answer:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

Step-by-step explanation:

A chi-square goodness of fit test determines if a sample data obtained fit to a specified population.

p_v represent the p value for the test

O= obserbed values

E= expected values

The system of hypothesis for this case are:

Null hypothesis: O_i = E_i[/tex[Alternative hypothesis: [tex]O_i \neq E_i

The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

On this case after calculate the statistic they got: \chi^2 = 11.517

And in order to calculate the p value we need to find first the degrees of freedom given by:

df=n-1=10-1=9, where k represent the number of levels (on this cas we have 10 categories)

And in order to calculate the p value we need to calculate the following probability:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

6 0
3 years ago
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