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choli [55]
3 years ago
5

What is the solution to this equation 4x+x-15+3-8x=13

Mathematics
1 answer:
Fynjy0 [20]3 years ago
3 0
5x -15 + 3 -8x = 13
5x  -12 -8x = 13
5x -8x =13 -12
-3x = 1
x = -1/3
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Jamal has $15.00 to spend at the concession stand. He buys nachos for $7.50, and he wants to purchase some sour straws for $1.50
GalinKa [24]

Answer:

x = 5

$15.00 is the total amount of money Jamal has right? To find the remaining amount of money Jamal has subtract 15 - 7.5 (price of nachos) = 7.5 (remaining amount of money Jamal has.) Now for part 2, since the sour straws are $1.50 each you just have to multiply X to get close as close to the remaining amount of money as possible.

1.50× 5 (amount of sour straws) is equal to 7.50 (price of 5 sour straws).

To check your answer let's add the price of nachos (7.50) and 5 sour straws (7.50) which is 15.00 the total amount Jamal brought with him.

Let me know if you have any other questions :)

4 0
2 years ago
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-7x + 13<br> HELP I WILL CHOOSE BRAINLIEST TO BEST ANSWER
Leni [432]
search it up than you will get the correct answer
3 0
3 years ago
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Write an expression that I’d equivalent to 1/2a - 4. URGENT, LIMITED TIME.
SCORPION-xisa [38]

Answer:

1/2(a-4)

Step-by-step explanation:

first blank is 1/2 and second is 4.

7 0
2 years ago
If f(x) = 2x−5, then what is the value of f(2) + f(5)
DochEvi [55]
First of all f(2)=2(2)-5=-1 and f(5)=2(5)-5=5
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f(2)+f(3)=-1+5=4
7 0
3 years ago
Determine the first four terms of the sequence in which the nth term is
Licemer1 [7]

<u>Answer:</u>

The correct answer option is: \frac{1}{3} ,\frac{1}{4} ,\frac{1}{5} ,\frac{1}{6}.

<u>Step-by-step explanation:</u>

We know that the nth term a_n for an arithmetic sequence is given by:

a_n=\frac{(n+1)!}{(n+2)!}

where n is the number of the position of the term.

We are supposed to find the first four terms of the sequence so we will substitute the values of n from 1 to 4 in the given formula to get:

1st term:

a_1=\frac{(1+1)!}{(1+2)!}=\frac{1}{3}

2nd term:

a_2=\frac{(2+1)!}{(2+2)!}=\frac{1}{4}

3rd term:

a_3=\frac{(3+1)!}{(3+2)!}=\frac{1}{5}

4th term:

a_4=\frac{(4+1)!}{(4+2)!}=\frac{1}{6}

8 0
3 years ago
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