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2 years ago

What is the solution to this equation 4x+x-15+3-8x=13

Mathematics

1 answer:

Fynjy0 [20]2 years ago

3 0

5x -15 + 3 -8x = 13
5x -12 -8x = 13
5x -8x =13 -12
-3x = 1
x = -1/3

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3 years ago

The table below represents a linear function f(x) and the equation represents a function g(x):

Elza [17]

Answer:

(a) The slope of f(x) is greater than the slope of g(x)

(b) f(x) has a greater y intercept

Step-by-step explanation:

Given

$\begin{array}{cc}x & {f(x)} & -1&-9&0&-1&1&7 \ \end{array}$

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Solving (a): Compare the slopes

The slope (m) of f(x) is calculated as;

$m = \frac{f(x_2) - f(x_1)}{x_2 - x_1}$

This gives:

$m = \frac{f(0) - f(1)}{0 - 1}$

$m = \frac{f(0) - f(1)}{- 1}$

Substitute values for f(0) and f(1)

$m = \frac{-1 - 7}{- 1}$

$m = \frac{-8}{- 1}$

$m = 8$

The slope of g(x) can be gotten using the following comparison

$g(x) = mx + b$

$m \to slope$

So:

$g(x) = 3x -2$

$m = 3$

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Solving (b): Compare the y intercept

y intercept is when $x = 0$

From the table of f(x)

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2 years ago

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<h3>Solution:</h3>

$\sqrt{32} \times \sqrt{ \frac{1}{18} } \\ = \sqrt{32} \times \frac{ \sqrt{1} }{ \sqrt{18} } \\ = \sqrt{32} \times \frac{1}{ \sqrt{18} } \\ = \frac{\sqrt{2 \times 2 \times 2 \times 2 \times 2}}{ \sqrt{2 \times 3 \times 3} } \\ = \frac{ \sqrt{ {2}^{2} \times {2}^{2} \times 2} }{ \sqrt{2 \times {3}^{2} } } \\ = \frac{2 \times 2 \times \sqrt{2} }{3 \times \sqrt{2} } \\ = \frac{4 \times \sqrt{2} }{3 \times \sqrt{2} } \\ = \frac{4}{3}$