We can use the slope-intercept form. We know one point, so we can use its coordinates for x and y. We also know the slope, so we use the slope for m. Then we solve for b.
y = mx + b
Substitute m with the slope.
y = (3/4)x + b
Use the x-coordinate of the given point for x and the y-coordinate of the given point for y.
1 = (3/4)(-4) + b
Solve for b.
1 = -3 + b
b = 4
Now that we know the value of b, we can write the equation of the line.
It is quadratic, because the highest degree for x is 2, x². Expand the expression and you'll see: f(x)=3x²-3x-3x-7 simplify: f(x)=3x²-6x-7 the quadratic term is 3x², the linear term is -6x, the constant is -7