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2 years ago

Please help with this ASAP.

Mathematics

2 answers:

kolezko [41]2 years ago

8 0

Answer: Choice D

Explanation:

I'll use the point-slope form to get the following

$y - y_1 = m(x - x_1)\\\\y - 1 = \frac{3}{4}(x - (-4))\\\\y - 1 = \frac{3}{4}(x + 4)\\\\y - 1 = \frac{3}{4}x + \frac{3}{4}*4\\\\y - 1 = \frac{3}{4}x + 3\\\\y = \frac{3}{4}x + 3 + 1\\\\y = \frac{3}{4}x + 4 \ \ \text{... matches with choice D}\\\\$

You should find that plugging x = -4 into equation D will lead to y = 1 as a way to confirm the answer.

Ostrovityanka [42]2 years ago

7 0

Answer:

Step-by-step explanation:

m = 3/4

point: (-4, 1)

We can use the slope-intercept form. We know one point, so we can use its coordinates for x and y. We also know the slope, so we use the slope for m. Then we solve for b.

y = mx + b

Substitute m with the slope.

y = (3/4)x + b

Use the x-coordinate of the given point for x and the y-coordinate of the given point for y.

1 = (3/4)(-4) + b

Solve for b.

1 = -3 + b

b = 4

Now that we know the value of b, we can write the equation of the line.

y = mx + b; m = 3/4; b = 4

y = 3/4 x + 4

Answer: D

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3 solutions:

$\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}$

Step-by-step explanation:

So, first of all, we need to figure the angles that cannot be included in our answers out. The only function in the equation that isn't defined for some angles is $tan(\frac{\theta}{2})$ so let's focus on that part of the equation first.

We know that:

$tan(\frac{\theta}{2})=\frac{sin(\frac{\theta}{2})}{cos(\frac{\theta}{2})}$

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so we need to find the angles that will make the cos function equal to zero. So we get:

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we can now start plugging values in for n:

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