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katovenus [111]
3 years ago
13

What is the mass of the block of iron illustrated below?

Chemistry
2 answers:
Mandarinka [93]3 years ago
7 0
VOLUME= 5cm*10cm*2cm =100cm^3
but density of iron=7.874g/cm^3
mass=7.874g*100 =787.4g
mass of that block = 787.4g
Alexandra [31]3 years ago
5 0

Answer : 787.4 g

Explanation : With the given information; the volume of the block will be equal to = 5 cm X 10 cm X 2 cm = 100 cm^{3}.

Therefore, the volume will be 100 cm^{3}.

but density of iron is found to be 7.874 g/cm^{3}

So, now calculating for mass; on the basis of the density formula;

which is density = mass/volume; so, mass = density X volume;

Therefore, mass will be 7.874 g X 100 = 787.4 g

mass of the iron block = 787.4 g

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Answer:

<h3>25.0 grams is the mass of the steel bar.</h3>

Explanation:

Heat gained by steel bar will be equal to heat lost by the water

Q_1=-Q_2

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Q_2=m_2c_2\times (T-T_3)-Q_1=Q_2(m_1c_1\times (T-T_1))=-(m_2c_2\times (T-T_3))

On substituting all values:

(m_1\times 0.452 J/g^oC\times (21.50^o-2.00^oC))=-(105 g\times 4.18 J/g^oC\times (21.50^o-22.00^o))\\\\m_1*8.7914=241.395\\\\m_1=\frac{219.45}{8.7914} \\\\m_1=24.9\\\\ \approx25 \texttt {grams}

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